Relative lowering of vapour pressure is independent of T.
Osmotic pressure always depends on the nature of solute.
Elevation of boiling point is independent of nature of the solvent.
Lowering of freezing point is proportional to the molar concentration of solute.
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The Correct Option isA
Solution and Explanation
The correct statement is: Relative lowering of vapor pressure is independent of T.
Here's why:
Relative Lowering of Vapor Pressure: According to Raoult's Law, the relative lowering of vapor pressure is equal to the mole fraction of the solute: $\frac{P_0 - P_s}{P_0} = x_{solute}$ where:
P0 is the vapor pressure of the pure solvent
Ps is the vapor pressure of the solution
xsolute is the mole fraction of the solute
Osmotic Pressure: Osmotic pressure (π) is given by: $\pi = iMRT$ While molarity (M) and temperature (T) are involved, the van't Hoff factor (i) *can* be affected by the nature of the solute (e.g., whether it's an electrolyte or a nonelectrolyte), but it isn't *always* dependent on the nature of solute. Strong electrolytes dissociate completely into ions, but weak electrolytes only partially dissociate, and non-electrolytes do not dissociate at all. Furthermore, even for electrolytes, *ion pairing* becomes significant at higher concentrations.
Elevation of Boiling Point: The elevation of the boiling point (ΔTb) is given by: $\Delta T_b = K_b m$ where:
Kb is the ebullioscopic constant, which *depends on the solvent*
m is the molality of the solution
Lowering of Freezing Point: The depression of the freezing point (ΔTf) is given by: $\Delta T_f = K_f m$ where:
Kf is the cryoscopic constant, which depends on the *solvent*
m is the molality of the solution. While, at lower concentrations, molality is approximately equal to molarity, the phrase "molar concentration" is less accurate than "molality". This is a more subtle point, and the more relevant point is that Kf depends on the solvent.
Correct Answer: Relative lowering of vapor pressure is independent of T.