\(\text{Kolbe reaction}\)
\(\text{Williamson reaction}\)
\(\text{Etard reaction}\)
\(\text{Reimer-Tiemann reaction}\)
\(\text{Stephen reaction}\)
Step 1: Understanding the conversion of phenol to salicylaldehyde
The Reimer-Tiemann reaction is a specific organic reaction used to introduce an aldehyde (-CHO) group at the ortho position of phenol. The reaction involves treating phenol with chloroform (CHCl\(_3\)) and aqueous sodium hydroxide (NaOH), followed by acidification.
Step 2: Analyzing the given options
(A) Kolbe reaction – Converts phenol to salicylic acid, not salicylaldehyde.
(B) Williamson reaction – Used for the synthesis of ethers, not aldehydes.
(C) Etard reaction – Oxidizes alkyl groups to aldehydes, but phenol lacks an alkyl group.
(D) Reimer-Tiemann reaction – Correct reaction for converting phenol to salicylaldehyde.
(E) Stephen reaction – Used for converting nitriles to aldehydes, not applicable here.
Step 3: Conclusion The Reimer-Tiemann reaction is the correct method for synthesizing salicylaldehyde from phenol.
Thus, the correct answer is option (D).
If $ X = A \times B $, $ A = \begin{bmatrix} 1 & 2 \\-1 & 1 \end{bmatrix} $, $ B = \begin{bmatrix} 3 & 6 \\5 & 7 \end{bmatrix} $, find $ x_1 + x_2 $.