Question

P, Q and R are three consecutive odd numbers in ascending order. If the value of three times P is 3 less than two times R, find the value of R.

• A. 5
• B. 7
• C. 9
• D. 11

Hint:

For consecutive odd or even numbers, use arithmetic progression with difference 2.

Answer 1

The Correct Option is C

Let P = $n$, Q = $n+2$, R = $n+4$. Given: $3P = 2R - 3 \Rightarrow 3n = 2(n+4) - 3$ $3n = 2n + 8 - 3 \Rightarrow 3n = 2n + 5 \Rightarrow n = 5$ Thus, R = $n+4 = 9$.