Question:

$P$ and $Q$ are two distinct points on the parabola, $y^2 = 4x$, with parameters $t$ and $t_1$ respectively. If the normal at $P$ passes through $Q$, then the minimum value of $t^2_1$ is :

Updated On: Feb 14, 2025
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The Correct Option is D

Solution and Explanation

$t _{1}=- t -\frac{2}{ t }$ $t _{1}^{2}= t ^{2}+\frac{4}{ t ^{2}}+4$ $\min$ of $t _{1}^{2}=8$
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