Let AB be the line segment between the axes and let P (a, b) be its mid-point.
Let the coordinates of A and B be (0, y) and (x, 0) respectively.
Since P (a, b) is the mid-point of AB,
\(\left(\frac{0+x}{2},\frac{y+0}{2}\right)=(a,b)\)
\(⇒\left(\frac{x}{2},\frac{y}{2}\right)=(a,b)\)
\(⇒\frac{x}{2}=a\space and \space \frac{y}{2}=b\)
\(∴x=2a\) and \(y=2b\)
Thus, the respective coordinates of A and B are (0, 2b) and (2a, 0).
The equation of the line passing through points (0, 2b) and (2a, 0) is
\((y-2b)=\frac{\left(0-2b\right)}{\left(2a-0\right)}(x-0)\)
\(y-2b=\frac{-2b}{2a}(x)\)
\(a(y-2b)=-bx\)
\(i.e,bx+ay=2ab\)
On dividing both sides by \(ab\), we obtain
\(\frac{bx}{ab}+\frac{ay}{ab}=\frac{2ab}{ab}\)
\(⇒\frac{x}{a}+\frac{y}{b}=2\)
Thus, the equation of the line is \(\frac{x}{a}+\frac{y}{b}=2\)
Figures 9.20(a) and (b) refer to the steady flow of a (non-viscous) liquid. Which of the two figures is incorrect ? Why ?
A straight line is a line having the shortest distance between two points.
A straight line can be represented as an equation in various forms, as show in the image below:
The following are the many forms of the equation of the line that are presented in straight line-
Assume P0(x0, y0) is a fixed point on a non-vertical line L with m as its slope. If P (x, y) is an arbitrary point on L, then the point (x, y) lies on the line with slope m through the fixed point (x0, y0) if and only if its coordinates fulfil the equation below.
y – y0 = m (x – x0)
Let's look at the line. L crosses between two places. P1(x1, y1) and P2(x2, y2) are general points on L, while P (x, y) is a general point on L. As a result, the three points P1, P2, and P are collinear, and it becomes
The slope of P2P = The slope of P1P2 , i.e.
\(\frac{y-y_1}{x-x_1} = \frac{y_2-y_1}{x_2-x_1}\)
Hence, the equation becomes:
y - y1 =\( \frac{y_2-y_1}{x_2-x_1} (x-x1)\)
Assume that a line L with slope m intersects the y-axis at a distance c from the origin, and that the distance c is referred to as the line L's y-intercept. As a result, the coordinates of the spot on the y-axis where the line intersects are (0, c). As a result, the slope of the line L is m, and it passes through a fixed point (0, c). The equation of the line L thus obtained from the slope – point form is given by
y – c =m( x - 0 )
As a result, the point (x, y) on the line with slope m and y-intercept c lies on the line, if and only if
y = m x +c