The given compound is 2,3-dimethylbut-2-ene, which has the structure:
CH3–C(CH3)=C(CH3)–CH3
It is a symmetrical alkene (both sides of the double bond have identical groups).
When ozonolysis occurs, the C=C double bond is cleaved, and each of the doubly bonded carbons is converted into a carbonyl group (C=O).
The reaction can be represented as:
CH3–C(CH3)=C(CH3)–CH3 ⟶ (i) O3 ⟶ (ii) Zn / H2O ⟶ 2 CH3–CO–CH3
The product formed is acetone (propanone).
Therefore, the overall reaction gives: \[ 2,3\text{-dimethylbut-2-ene} \xrightarrow[\text{Zn/H}_2\text{O}]{\text{O}_3} 2\, \text{acetone} \]