Step 1: Understanding the Concept:
Order (O) of a differential equation is the order of the highest derivative appearing in the equation.
Degree (D) of a differential equation is the highest power (positive integer) of the highest order derivative, after the equation has been cleared of any radicals or fractional powers of the derivatives.
Step 2: Key Approach:
First, we need to eliminate the square root to make the equation a polynomial in terms of the derivatives. Then, we can identify the order and degree.
Step 3: Detailed Calculation:
The given differential equation is:
\[ \left(\frac{dy}{dx}\right)^3 = \sqrt{\frac{d^2y}{dx^2} + 10} \]
To remove the square root, we square both sides of the equation:
\[ \left( \left(\frac{dy}{dx}\right)^3 \right)^2 = \left( \sqrt{\frac{d^2y}{dx^2} + 10} \right)^2 \]
This simplifies to:
\[ \left(\frac{dy}{dx}\right)^6 = \frac{d^2y}{dx^2} + 10 \]
Now the equation is free from radicals.
Finding the Order (O):
The derivatives present in the equation are \(\frac{dy}{dx}\) (1st order) and \(\frac{d^2y}{dx^2}\) (2nd order).
The highest order derivative is \(\frac{d^2y}{dx^2}\).
Therefore, the Order (O) = 2.
Finding the Degree (D):
The degree is the power of the highest order derivative, which is \(\frac{d^2y}{dx^2}\).
In the equation \(\left(\frac{dy}{dx}\right)^6 = \frac{d^2y}{dx^2} + 10\), the term with the highest derivative is \(\left(\frac{d^2y}{dx^2}\right)^1\).
The power of this term is 1.
Therefore, the Degree (D) = 1.
Step 4: Final Answer:
The order is 2 and the degree is 1.
Step 5: Why This is Correct:
The calculation correctly follows the definitions of order and degree. A common mistake is to state the degree is 6, but the degree is determined by the power of the highest *order* derivative (\(d^2y/dx^2\)), not the highest power of any derivative.