Mass of the whole disc = 4M
Moment of inertia of the disc about the given axis
$ \, \, \, \, \, \, \, \, \, = \frac{1}{2} (4M) R^2 = 2MR^2$
$ \therefore $ Moment of inertia of quarter section of the disc
$ \, \, \, \, \, \, \, \, \, = \frac{1}{4} (2M R^2 )= \frac{1}{2}MR^2$