One end of a string of length l is connected to a particle of mass m and the other to a small peg on a smooth horizontal table. If the particle moves in a circle with speed v the net force on the particle (directed towards the centre) is:
- \(\text T\)
- \(\text T- \frac{mv^2}{l}\)
- \(\text T+ \frac{mv^2}{l}\)
- 0
The Correct Option is A
Solution and Explanation
When a particle connected to a string revolves in a circular path around a centre, the centripetal force is provided by the tension produced in the string. Hence, in the given case, the net force on the particle is the tension \(\text T\), i.e.,
\(\text F\) = \(\text T\) = \(\frac{mv^2}{l}\)
Where \(\text F\) is the net force acting on the particle.
Therefore, the correct option is (a): \(\text T\)
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Concepts Used:
Centripetal Forces
- The centripetal force makes a move on the object traveling in a circular direction and is directed towards the center upon which the object is moving.
- Centripetal force emanates from the gravitational pull and electrostatic force.
- It is a real force acting on both inertial frames and non-inertial frames.
- The centripetal force formula is
- From the object to the center is the exact direction of centripetal forces.
- The centripetal force has the tendency to turn towards the center.
- Centripetal force makes us set foot in a circular motion.