On comparing the ratios\( \dfrac{a_1}{a_2},\) \(\dfrac{b_1}{b_2}\), and \(\dfrac{c_1}{c_2}\), find out whether the following pair of linear equations are consistent, or inconsistent.(i) \(3x + 2y = 5 ; 2x – 3y = 7\) (ii) \(2x – 3y = 8 ; 4x – 6y = 9\) (iii) \(\dfrac{3}{2x} + \dfrac{5}{3y} =7\) ; \(9x – 10y = 14\) (iv) \(5x – 3y = 11 \) ;\( – 10x + 6y = –22\) (v)\( \dfrac{4}{3x} +2y =8; 2x + 3y = 12\)
(i)\( 3x + 2y = 5 , 2x − 3y = 7 \)
\(\dfrac{a_1}{a_2} =\dfrac{3}{2}, \dfrac{b_1}{b_2} =\dfrac{-2}{3}, \dfrac{c_1}{c_2} =\dfrac{5}{7}\)
\(\dfrac{a_1}{a_2}≠ \dfrac{b_1}{b_2}\);
These linear equations are intersecting each other at one point and thus have only one possible solution. Hence, the pair of linear equations is consistent.
(ii) \(2x − 3y = 8 4x − 6y = 9\)
\(\dfrac{a_1}{a_2} =\dfrac{2}{4}= \dfrac{1}{2} , \dfrac{b_1}{b_2} = \dfrac{-3}{-6} = \dfrac{1}{2} , \dfrac{c_1}{c_2} = \dfrac{8}{9}\)
Since, \( \dfrac{a_1}{a_2} = \dfrac{b_1}{b_2} ≠ \dfrac{c_1}{c_2}\)
Therefore, these linear equations are parallel to each other and thus have no possible solution. Hence, the pair of linear equations is inconsistent.
(iii) \(\dfrac{3}{2 x}\) +\(\dfrac{5}{3y} =7\)
\(9x -10y =14\)
\(\dfrac{a_1}{a_2} = \dfrac{3}{22/9} =\dfrac{1}{6}\), \(\dfrac{b_1}{b_2} =\dfrac{5}{3/(-10)} =\)\(\dfrac{-1}{6}\) , \(\dfrac{c_1}{c_2}\) =\( \dfrac{7}{14} = \dfrac{1}{2}\)
Since \(\dfrac{a_1}{a_2}≠ \dfrac{b_1}{b_2}\);
Therefore, these linear equations are intersecting each other at one point and thus have only one possible solution. Hence, the pair of linear equations is consistent.
(iv)\( 5x − 3 y = 11 \)
\(− 10x + 6y = − 22\)
\(\dfrac{a_1}{a_2} = \dfrac{5}{-10} = \dfrac{-1}{2} , \dfrac{b_1}{b_2} = \dfrac{-3}{6} =\dfrac{-1}{2}, \dfrac{c_1}{c_2} = \dfrac{11}{-22}= \dfrac{-1}{2}\)
Since, \(\dfrac{a_1}{a_2} =\dfrac{b_1}{b_2} =\dfrac{c_1}{c_2}\)
Therefore, these linear equations are coincident pairs of lines and thus have an infinite number of possible solutions. Hence, the pair of linear equations is consistent.
(v) \(\dfrac{4}{3x} +2y =8\)
\(2x +3y =12 \)
\(\dfrac{a_1}{a_2} = \dfrac{4}{3/2} = \dfrac{2}{3} , \dfrac{b_1}{b_2} =\dfrac{2}{3} , \dfrac{c_1}{c_2} =\dfrac{9}{12} =\dfrac{2}{3}\)
Since, \(\dfrac{a_1}{a_2} = \dfrac{b_1}{b_2} = \dfrac{c_1}{c_2}\)
Therefore, these linear equations are coincident pairs of lines and thus have an infinite number of possible solutions. Hence, the pair of linear equations is consistent.
Draw the graphs of the equations \(x – y + 1 = 0 \)and \(3x + 2y – 12 = 0\). Determine the coordinates of the vertices of the triangle formed by these lines and the \(X\)-axis, and shade the triangular region.
Half the perimeter of a rectangular garden, whose length is \(4 \) m more than its width is \(36\) m. Find the dimensions of the garden
Graphical representation needs the plotting of the x and y in graph paper. Plotting the x and y values of the equation on the coordinate plane. For plotting the graph you will be needed at least 3 sets of points. It is very much important for those points to fall in a straight line. If the points are haphazardly placed, it will indicate some fault in your work.
On the graph paper, draw the x and y-axis. Simply, the x and y-axis are two number lines that are placed perpendicular to each other at the (0,0) point. This point is known to be the origin. Use the aforesaid values for plotting the points. Join all of these points with a straight line.