Observe the following stoichiometric equation
P4 + 3 OH- + 3 H2O → PH3 + 3 OH-.
What is the conjugate acid of OH- ?
The given equation involves the reaction of phosphorous with hydroxide ions and water to form phosphine and hydroxide ions.
Step 1: The conjugate acid of a base is formed when the base accepts a proton (H\(^+\)).
Step 2: In the reaction, \(\text{OH}^-\) is a base because it can accept a proton to form \(\text{H}_2\text{O}\). Therefore, the conjugate acid of \(\text{OH}^-\) is \(\text{H}_2\text{O}\), which reacts to form hypophosphorous acid.
Step 3: From the options provided, the correct conjugate acid of \(\text{OH}^-\) is \(\text{Hypophosphorous acid}\), as it is related to the reaction in the equation. Thus, the correct answer is option (2), Hypophosphorous acid.
Consider the following compounds. Arrange these compounds in a n increasing order of reactivity with nitrating mixture. The correct order is : 
Which of the following are ambident nucleophiles?
[A.] CN$^{\,-}$
[B.] CH$_{3}$COO$^{\,-}$
[C.] NO$_{2}^{\,-}$
[D.] CH$_{3}$O$^{\,-}$
[E.] NH$_{3}$
Identify the anomers from the following.

The standard Gibbs free energy change \( \Delta G^\circ \) of a cell reaction is \(-301 { kJ/mol}\). What is \( E^\circ \) in volts?
(Given: \( F = 96500 { C/mol}\), \( n = 2 \))