Observe the following stoichiometric equation
P4 + 3 OH- + 3 H2O → PH3 + 3 OH-.
What is the conjugate acid of OH- ?
Observe the following stoichiometric equation
P4 + 3 OH- + 3 H2O → PH3 + 3 OH-.
What is the conjugate acid of OH- ?
Show Hint
- Phosphorous acid
- Hypophosphorous acid
- Phosphoric acid
- Pyrophosphoric acid
The Correct Option is B
Solution and Explanation
The given equation involves the reaction of phosphorous with hydroxide ions and water to form phosphine and hydroxide ions.
Step 1: The conjugate acid of a base is formed when the base accepts a proton (H\(^+\)).
Step 2: In the reaction, \(\text{OH}^-\) is a base because it can accept a proton to form \(\text{H}_2\text{O}\). Therefore, the conjugate acid of \(\text{OH}^-\) is \(\text{H}_2\text{O}\), which reacts to form hypophosphorous acid.
Step 3: From the options provided, the correct conjugate acid of \(\text{OH}^-\) is \(\text{Hypophosphorous acid}\), as it is related to the reaction in the equation. Thus, the correct answer is option (2), Hypophosphorous acid.
Top Questions on Chemical Kinetics
- For the reaction: \[ 2A + B \rightarrow 3C \] The rate law is given as: \[ \text{Rate} = k[A]^2[B] \] If the concentration of A is doubled and the concentration of B is halved, how does the rate of the reaction change?
- MHT CET - 2025
- Chemistry
- Chemical Kinetics
In the given graph, \( E_a \) for the reverse reaction will be
- KCET - 2025
- Chemistry
- Chemical Kinetics
- For the reaction \( \text{2N}_2\text{O}_5 \rightarrow 4\text{NO}_2 (g) + \text{O}_2 (g) \), the initial concentration of \( \text{N}_2\text{O}_5 \) is 2.0 mol L\(^{-1}\), and after 300 minutes, it is reduced to 1.4 mol L\(^{-1}\). The rate of production of \( \text{NO}_2 \) (in mol L\(^{-1}\) min\(^{-1}\)) is
- KCET - 2025
- Chemistry
- Chemical Kinetics
- Half-life of a first order reaction is 20 seconds and initial concentration of reactant is 0.2M. The concentration of reactant left after 80 seconds is
- KCET - 2025
- Chemistry
- Chemical Kinetics
- The rate constant for a first-order reaction is \( 0.0693 \, \text{min}^{-1} \). What is the half-life of the reaction?
- MHT CET - 2025
- Chemistry
- Chemical Kinetics
Questions Asked in AP EAMCET exam
- If \(\int \frac{\log(1+x^4)}{x^3} dx = f(x) \log(\frac{1}{g(x)}) + \tan^{-1}(h(x)) + c\), then \(h(x) [f(x) + f(\frac{1}{x})] =\)
- AP EAMCET - 2024
- Integration
- Initially the pressure of 1 mole of an ideal gas is \( 10^5 \) Nm\(^2\) and its volume is 16 liters. When it is adiabatically compressed, its final volume is 2 liters. Work done on the gas is (molar specific heat at constant volume \( C_V = \frac{3R}{2} \)):
- AP EAMCET - 2024
- Thermodynamics
- A ball at point ‘O’ is at a horizontal distance of 7 m from a wall. On the wall, a target is set at point ‘C’. If the ball is thrown from ‘O’ at an angle \( 37^\circ \) with horizontal aiming the target ‘C’. But it hits the wall at point ‘D’ which is a vertical distance \( y_0 \) below ‘C’. If the initial velocity of the ball is 15 m/s, find \( y_0 \). (Given \( \cos 37^\circ = \frac{4}{5} \))
- AP EAMCET - 2024
- projectile motion
- If \( 4x - 3y - 5 = 0 \) is a normal to the ellipse \( 3x^2 + 8y^2 = k \), then the equation of the tangent at point (-2,m) is:
- If the roots of the quadratic equation \( x^2 - 35x + c = 0 \) are in the ratio 2:3 and \( c = 6K \), then \( K \) is:
- AP EAMCET - 2024
- Quadratic Equations