Question:

Observe the following reactions (g = gas):
I. N$_2$(g) + 3H$_2$(g) $\xrightarrow[\text{200 atm}]{\text{773K, X}}$ 2NH$_3$(g)
II. CO(g) + H$_2$O(g) $\xrightarrow[\text{673 K}]{\text{Y}}$ CO$_2$(g) + H$_2$(g)
III. CH$_4$(g) + H$_2$O(g) $\xrightarrow[\text{1270 K}]{\text{Z}}$ CO(g) + 3H$_2$(g)
Catalysts X, Y, Z respectively are

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Haber-Bosch: Fe. Water-gas shift: FeCrO$_4$. Steam reforming: Ni.
Updated On: Jun 5, 2025
  • Iron, sodium arsenite, cobalt
  • Iron, zinc, cobalt
  • Cobalt, zinc, nickel
  • Iron, iron chromate, nickel
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The Correct Option is D

Solution and Explanation

Reaction I (Haber-Bosch process): The catalyst used is iron (Fe) with small amounts of promoters like potassium oxide and aluminum oxide.
Reaction II (Water-gas shift reaction): The catalyst used is iron chromate (FeCrO$_4$) or a high-temperature catalyst like iron oxide (Fe$_3$O$_4$) promoted by chromium oxide (Cr$_2$O$_3$).
Reaction III (Steam reforming of methane): The catalyst used is nickel (Ni) on a support like alumina (Al$_2$O$_3$).
Therefore, the catalysts X, Y, and Z are Iron, Iron chromate, and Nickel, respectively.
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