Question:
In Solvay process, $\mathrm{NH_3}$ is recovered when the solution containing $\mathrm{NH_4Cl}$ is treated with compound ‘X’. What is ‘X’?
In Solvay process, $\mathrm{NH_3}$ is recovered when the solution containing $\mathrm{NH_4Cl}$ is treated with compound ‘X’. What is ‘X’?
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In the Solvay process, \(\mathrm{Ca(OH)_2}\) is used to recover ammonia by reacting with \(\mathrm{NH_4Cl}\).
Updated On: Jun 4, 2025
- \(\mathrm{Ca(OH)_2}\)
- \(\mathrm{CaCl_2}\)
- \(\mathrm{NaOH}\)
- \(\mathrm{NaCl}\)
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The Correct Option is A
Solution and Explanation
In the Solvay process: Ammonia recovery occurs by treating ammonium chloride with calcium hydroxide: \[ 2\mathrm{NH_4Cl} + \mathrm{Ca(OH)_2} \rightarrow 2\mathrm{NH_3} + \mathrm{CaCl_2} + 2\mathrm{H_2O} \] This reaction regenerates \(\mathrm{NH_3}\), which is reused in the process.
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