Question

Observe the following compounds/ions: \[ H_3BO_3, \, [B(OH)_4]^-, \, BH_4^-, \, [BCI_3 \cdot NH_3], \, SiO_4^{2-} \] The number of compounds/ions with tetrahedral shape is:

• A. 5
• B. 4
• C. 2
• D. 3 \

Hint:

- A tetrahedral structure is formed when an atom is surrounded by four other atoms or groups arranged at the vertices of a tetrahedron. - Look for molecules/ions where the central atom is bonded to four substituents or ligands.

Answer 1

The Correct Option is B

Step 1: Analyzing the tetrahedral structure of each compound: \begin{itemize} \item \( H_3BO_3 \): This molecule has a trigonal planar structure, not tetrahedral. \item \( [B(OH)_4]^- \): The structure of this ion is tetrahedral, as boron is surrounded by four OH groups in a tetrahedral arrangement. \item \( BH_4^- \): This molecule also has a tetrahedral structure, as boron is surrounded by four hydrogen atoms in a tetrahedral shape. \item \( [BCI_3 \cdot NH_3] \): The boron atom in this compound is surrounded by three chlorine atoms and one ammonia molecule, resulting in a tetrahedral geometry. \item \( SiO_4^{2-} \): The silicate ion has a tetrahedral shape as the silicon atom is surrounded by four oxygen atoms in a tetrahedral arrangement. \end{itemize} Thus, the number of compounds/ions with tetrahedral shape is four.