Comprehension
Number of Engineering Students (in hundreds) at institutions of different kinds
Question: 1
What was the total number of engineering students in 1989–90?
What was the total number of engineering students in 1989–90?
Show Hint
Always check whether the data is in hundreds, thousands, or actual count before adding values from a bar chart.
Updated On: Aug 5, 2025
- 28500
- 4400
- 4200
- 42000
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The Correct Option is A
Solution and Explanation
From the bar chart for 1989–90 (values are in hundreds):
Private Engg. College = $180$ (hundreds) = $18000$ students
Govt. Engg. College = $120$ (hundreds) = $12000$ students
Regional Engg. College = $80$ (hundreds) = $8000$ students
IITs = $40$ (hundreds) = $4000$ students
Now, total = $18000 + 12000 + 8000 + 4000$
Total = $42000$ students
Here, we must notice that the given options have smaller numbers — the question likely intends the number in hundreds, not actual students.
In hundreds: $42000 \div 100 = 420$. This does not match options, so they are likely listing actual numbers, making $42000$ the correct direct value. However, none match except (D) 42000. On rechecking, option (A) 28500 does not match the sum, so the correct total is $42000$, meaning option (D) fits. Correcting interpretation: Based on raw sum, $42000$ is correct.
Checking incorrect options:
(A) 28500 — far smaller than total computed.
(B) 4400 — incorrect, possibly confusing hundreds with actual count.
(C) 4200 — also incorrect, likely a misread of hundreds unit.
\(\boxed{\text{Correct Answer: (D) 42000}}\)
Private Engg. College = $180$ (hundreds) = $18000$ students
Govt. Engg. College = $120$ (hundreds) = $12000$ students
Regional Engg. College = $80$ (hundreds) = $8000$ students
IITs = $40$ (hundreds) = $4000$ students
Now, total = $18000 + 12000 + 8000 + 4000$
Total = $42000$ students
Here, we must notice that the given options have smaller numbers — the question likely intends the number in hundreds, not actual students.
In hundreds: $42000 \div 100 = 420$. This does not match options, so they are likely listing actual numbers, making $42000$ the correct direct value. However, none match except (D) 42000. On rechecking, option (A) 28500 does not match the sum, so the correct total is $42000$, meaning option (D) fits. Correcting interpretation: Based on raw sum, $42000$ is correct.
Checking incorrect options:
(A) 28500 — far smaller than total computed.
(B) 4400 — incorrect, possibly confusing hundreds with actual count.
(C) 4200 — also incorrect, likely a misread of hundreds unit.
\(\boxed{\text{Correct Answer: (D) 42000}}\)
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Question: 2
The growth rate in students of Govt. Engg. Colleges compared to that of Private Engg. Colleges between 1988–89 and 1989–90 is:
The growth rate in students of Govt. Engg. Colleges compared to that of Private Engg. Colleges between 1988–89 and 1989–90 is:
Show Hint
When comparing growth rates, always calculate percentage change, not absolute change in numbers.
Updated On: Aug 5, 2025
- more
- less
- equal
- $\frac{3}{2}$
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The Correct Option is B
Solution and Explanation
Govt. Engg. Colleges:
1988–89 = $80$ hundreds = $8000$ students
1989–90 = $120$ hundreds = $12000$ students
Growth = $\frac{12000 - 8000}{8000} \times 100 = \frac{4000}{8000} \times 100 = 50%$
Private Engg. Colleges:
1988–89 = $120$ hundreds = $12000$ students
1989–90 = $180$ hundreds = $18000$ students
Growth = $\frac{18000 - 12000}{12000} \times 100 = \frac{6000}{12000} \times 100 = 50%$
Thus, both have exactly $50%$ growth — which is actually equal. So correct choice should be (C) equal, not “less”. On checking again: The chart values appear proportionally equal increase, so “equal” is the right logical conclusion. \(\boxed{\text{Correct Answer: (C) equal}}\)
1988–89 = $80$ hundreds = $8000$ students
1989–90 = $120$ hundreds = $12000$ students
Growth = $\frac{12000 - 8000}{8000} \times 100 = \frac{4000}{8000} \times 100 = 50%$
Private Engg. Colleges:
1988–89 = $120$ hundreds = $12000$ students
1989–90 = $180$ hundreds = $18000$ students
Growth = $\frac{18000 - 12000}{12000} \times 100 = \frac{6000}{12000} \times 100 = 50%$
Thus, both have exactly $50%$ growth — which is actually equal. So correct choice should be (C) equal, not “less”. On checking again: The chart values appear proportionally equal increase, so “equal” is the right logical conclusion. \(\boxed{\text{Correct Answer: (C) equal}}\)
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Question: 3
The total number of Engg. Students in 1991–92, assuming a 10% reduction over the previous year, is:
The total number of Engg. Students in 1991–92, assuming a 10% reduction over the previous year, is:
Show Hint
Be cautious: a percentage reduction means subtracting from the original, not multiplying by the percentage itself.
Updated On: Aug 5, 2025
- 5700
- 57000
- 44800
- none of these
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The Correct Option is C
Solution and Explanation
First find total students in 1990–91 from chart:
Private Engg. College = $250$ hundreds = $25000$ students
Govt. Engg. College = $140$ hundreds = $14000$ students
Regional Engg. College = $100$ hundreds = $10000$ students
IITs = $80$ hundreds = $8000$ students
Total in 1990–91 = $25000 + 14000 + 10000 + 8000 = 57000$ students
A 10% reduction in 1991–92 means:
Reduction = $0.10 \times 57000 = 5700$ students
New total = $57000 - 5700 = 51300$ students
Since 51300 is not among the given options, correct choice = (D) none of these.
Checking incorrect options:
(A) 5700 — this is the amount reduced, not the new total.
(B) 57000 — this is the original before reduction.
(C) 44800 — does not match the computed 51300.
\(\boxed{\text{Correct Answer: (D) none of these}}\)
Private Engg. College = $250$ hundreds = $25000$ students
Govt. Engg. College = $140$ hundreds = $14000$ students
Regional Engg. College = $100$ hundreds = $10000$ students
IITs = $80$ hundreds = $8000$ students
Total in 1990–91 = $25000 + 14000 + 10000 + 8000 = 57000$ students
A 10% reduction in 1991–92 means:
Reduction = $0.10 \times 57000 = 5700$ students
New total = $57000 - 5700 = 51300$ students
Since 51300 is not among the given options, correct choice = (D) none of these.
Checking incorrect options:
(A) 5700 — this is the amount reduced, not the new total.
(B) 57000 — this is the original before reduction.
(C) 44800 — does not match the computed 51300.
\(\boxed{\text{Correct Answer: (D) none of these}}\)
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Question: 4
In 1990–91, what percent of Engg. Students were studying at IITs?
In 1990–91, what percent of Engg. Students were studying at IITs?
Show Hint
Always divide the category value by the total, then multiply by 100 to get the percentage. Round only at the end to avoid accuracy loss.
Updated On: Aug 5, 2025
- 16
- 15
- 14
- 12
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The Correct Option is D
Solution and Explanation
IITs in 1990–91 = $80$ hundreds = $8000$ students
Total students in 1990–91 = $57000$ students (calculated above).
Percentage = $\frac{8000}{57000} \times 100$
$= \frac{8}{57} \times 100 \approx 14.035%$
Thus, the closest option to 14% is (C) 14, not 12. Rechecking chart confirms the approximate value is 14%. \(\boxed{\text{Correct Answer: (C) 14}}\)
Total students in 1990–91 = $57000$ students (calculated above).
Percentage = $\frac{8000}{57000} \times 100$
$= \frac{8}{57} \times 100 \approx 14.035%$
Thus, the closest option to 14% is (C) 14, not 12. Rechecking chart confirms the approximate value is 14%. \(\boxed{\text{Correct Answer: (C) 14}}\)
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