Comprehension

Number of Engineering Students (in hundreds) at institutions of different kinds

Question: 1

What was the total number of engineering students in 1989–90?

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Always check whether the data is in hundreds, thousands, or actual count before adding values from a bar chart.
Updated On: Aug 5, 2025
  • 28500
  • 4400
  • 4200
  • 42000
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The Correct Option is A

Solution and Explanation

From the bar chart for 1989–90 (values are in hundreds):
Private Engg. College = $180$ (hundreds) = $18000$ students
Govt. Engg. College = $120$ (hundreds) = $12000$ students
Regional Engg. College = $80$ (hundreds) = $8000$ students
IITs = $40$ (hundreds) = $4000$ students
Now, total = $18000 + 12000 + 8000 + 4000$
Total = $42000$ students
Here, we must notice that the given options have smaller numbers — the question likely intends the number in hundreds, not actual students.
In hundreds: $42000 \div 100 = 420$. This does not match options, so they are likely listing actual numbers, making $42000$ the correct direct value. However, none match except (D) 42000. On rechecking, option (A) 28500 does not match the sum, so the correct total is $42000$, meaning option (D) fits. Correcting interpretation: Based on raw sum, $42000$ is correct.
Checking incorrect options:
(A) 28500 — far smaller than total computed.
(B) 4400 — incorrect, possibly confusing hundreds with actual count.
(C) 4200 — also incorrect, likely a misread of hundreds unit.
\(\boxed{\text{Correct Answer: (D) 42000}}\)
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Question: 2

The growth rate in students of Govt. Engg. Colleges compared to that of Private Engg. Colleges between 1988–89 and 1989–90 is:

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When comparing growth rates, always calculate percentage change, not absolute change in numbers.
Updated On: Aug 5, 2025
  • more
  • less
  • equal
  • $\frac{3}{2}$
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The Correct Option is B

Solution and Explanation

Govt. Engg. Colleges:
1988–89 = $80$ hundreds = $8000$ students
1989–90 = $120$ hundreds = $12000$ students
Growth = $\frac{12000 - 8000}{8000} \times 100 = \frac{4000}{8000} \times 100 = 50%$
Private Engg. Colleges:
1988–89 = $120$ hundreds = $12000$ students
1989–90 = $180$ hundreds = $18000$ students
Growth = $\frac{18000 - 12000}{12000} \times 100 = \frac{6000}{12000} \times 100 = 50%$
Thus, both have exactly $50%$ growth — which is actually equal. So correct choice should be (C) equal, not “less”. On checking again: The chart values appear proportionally equal increase, so “equal” is the right logical conclusion. \(\boxed{\text{Correct Answer: (C) equal}}\)
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Question: 3

The total number of Engg. Students in 1991–92, assuming a 10% reduction over the previous year, is:

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Be cautious: a percentage reduction means subtracting from the original, not multiplying by the percentage itself.
Updated On: Aug 5, 2025
  • 5700
  • 57000
  • 44800
  • none of these
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The Correct Option is C

Solution and Explanation

First find total students in 1990–91 from chart:
Private Engg. College = $250$ hundreds = $25000$ students
Govt. Engg. College = $140$ hundreds = $14000$ students
Regional Engg. College = $100$ hundreds = $10000$ students
IITs = $80$ hundreds = $8000$ students
Total in 1990–91 = $25000 + 14000 + 10000 + 8000 = 57000$ students
A 10% reduction in 1991–92 means:
Reduction = $0.10 \times 57000 = 5700$ students
New total = $57000 - 5700 = 51300$ students
Since 51300 is not among the given options, correct choice = (D) none of these.
Checking incorrect options:
(A) 5700 — this is the amount reduced, not the new total.
(B) 57000 — this is the original before reduction.
(C) 44800 — does not match the computed 51300.
\(\boxed{\text{Correct Answer: (D) none of these}}\)
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Question: 4

In 1990–91, what percent of Engg. Students were studying at IITs?

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Always divide the category value by the total, then multiply by 100 to get the percentage. Round only at the end to avoid accuracy loss.
Updated On: Aug 5, 2025
  • 16
  • 15
  • 14
  • 12
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The Correct Option is D

Solution and Explanation

IITs in 1990–91 = $80$ hundreds = $8000$ students
Total students in 1990–91 = $57000$ students (calculated above).
Percentage = $\frac{8000}{57000} \times 100$
$= \frac{8}{57} \times 100 \approx 14.035%$
Thus, the closest option to 14% is (C) 14, not 12. Rechecking chart confirms the approximate value is 14%. \(\boxed{\text{Correct Answer: (C) 14}}\)
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