Given: \( N^2 \equiv 1 \pmod{24} \).
This means that the square of \( N \) leaves a remainder of 1 when divided by 24.
Now, we want to find the possible remainders when \( N \) is divided by 12.
Step 1: Find the possible values of \( N \mod 24 \)
The equation \( N^2 \equiv 1 \pmod{24} \) implies that \( N^2 - 1 \) is divisible by 24. Therefore, \( N^2 - 1 = (N - 1)(N + 1) \) is divisible by 24.
This condition is satisfied when \( N \equiv 1, 5, 7, 11 \pmod{12} \). We check:
- \( N \equiv 1 \pmod{12} \) implies \( N^2 \equiv 1^2 = 1 \pmod{24} \),
- \( N \equiv 5 \pmod{12} \) implies \( N^2 \equiv 5^2 = 25 \equiv 1 \pmod{24} \),
- \( N \equiv 7 \pmod{12} \) implies \( N^2 \equiv 7^2 = 49 \equiv 1 \pmod{24} \),
- \( N \equiv 11 \pmod{12} \) implies \( N^2 \equiv 11^2 = 121 \equiv 1 \pmod{24} \).
Thus, the possible remainders when \( N \) is divided by 12 are 1, 5, 7, and 11.
Final Answer: The correct answer is (a) 1, 5, 7 and 11.