Step 1: Understanding the Concept:
This problem involves two trips along the same path at different speeds, with a given total time. We can set up an equation relating the times for each part of the journey to the total time.
Step 2: Key Formula or Approach:
Let \(d\) be the one-way distance of the trail.
Let \(v_{up}\) be the speed going up and \(v_{down}\) be the speed going down.
Let \(t_{up}\) be the time going up and \(t_{down}\) be the time going down.
We know that Time = Distance / Speed. So, \(t_{up} = \frac{d}{v_{up}}\) and \(t_{down} = \frac{d}{v_{down}}\).
The total time is given: \(T_{total} = t_{up} + t_{down}\).
Step 3: Detailed Explanation:
From the problem, we have:
- Speed up, \(v_{up} = 6\) mph.
- Speed down, \(v_{down} = 14\) mph.
- Total time, \(T_{total} = 1\) hour.
Using the formulas from Step 2, we can set up the equation for the total time:
\[ \frac{d}{v_{up}} + \frac{d}{v_{down}} = T_{total} \]
Substitute the known values into the equation:
\[ \frac{d}{6} + \frac{d}{14} = 1 \]
To solve for \(d\), we need to find a common denominator for 6 and 14. The least common multiple (LCM) of 6 and 14 is 42.
Multiply the entire equation by 42 to eliminate the fractions:
\[ 42 \left( \frac{d}{6} \right) + 42 \left( \frac{d}{14} \right) = 42(1) \]
\[ 7d + 3d = 42 \]
Combine the terms with \(d\):
\[ 10d = 42 \]
Solve for \(d\):
\[ d = \frac{42}{10} = 4.2 \text{ miles} \]
The question asks for the approximate number of miles for the one-way trail. The value 4.2 is closest to 4.
Step 4: Final Answer:
The trail is approximately 4 miles one way.