Step 1: Understanding the Concept:
This problem involves simplifying an expression with scientific notation and solving for the difference between two exponents, \(x-y\). The phrase "y less than x" translates to the expression \(x-y\).
Step 2: Key Formula or Approach:
We will use the rules of exponents:
\( a^m \times a^n = a^{m+n} \)
\( \frac{a^m}{a^n} = a^{m-n} \)
The first step is to convert the decimal coefficients into a consistent format, preferably standard scientific notation.
Step 3: Detailed Explanation:
Let's rewrite the decimal numbers in the expression:
\[ 0.0027 = 2.7 \times 10^{-3} \]
\[ 0.09 = 9 \times 10^{-2} \]
Substitute these back into the original equation:
\[ \frac{(2.7 \times 10^{-3}) \times 10^x}{(9 \times 10^{-2}) \times 10^y} = 3 \times 10^8 \]
Now, group the coefficients and the powers of 10 separately:
\[ \left( \frac{2.7}{9} \right) \times \left( \frac{10^{-3} \times 10^x}{10^{-2} \times 10^y} \right) = 3 \times 10^8 \]
Simplify the coefficient part:
\[ \frac{2.7}{9} = \frac{27}{90} = \frac{3}{10} = 0.3 \]
Simplify the powers of 10 using exponent rules:
\[ \frac{10^{-3+x}}{10^{-2+y}} = 10^{(-3+x) - (-2+y)} = 10^{x - y - 3 + 2} = 10^{x - y - 1} \]
Now the equation becomes:
\[ 0.3 \times 10^{x - y - 1} = 3 \times 10^8 \]
To solve this, we need the coefficient on the left to match the coefficient on the right. Let's write 0.3 in scientific notation as \(3 \times 10^{-1}\):
\[ (3 \times 10^{-1}) \times 10^{x - y - 1} = 3 \times 10^8 \]
Combine the powers of 10 on the left side:
\[ 3 \times 10^{-1 + (x - y - 1)} = 3 \times 10^8 \]
\[ 3 \times 10^{x - y - 2} = 3 \times 10^8 \]
Since the bases (3 and 10) are equal on both sides, the exponents of 10 must also be equal:
\[ x - y - 2 = 8 \]
Solve for \(x-y\):
\[ x - y = 8 + 2 \]
\[ x - y = 10 \]
Step 4: Final Answer
The value of y less than x, which is \(x-y\), is 10.