Question:

Mean free path of a gas molecule is

Updated On: Jun 4, 2024
  • inversely proportional to number of molecules per unit volume
  • inversely proportional to diameter of the molecule
  • directly proportional to the square root of the absolute temperature
  • directly proportional to the molecular mass
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The Correct Option is A

Solution and Explanation

Mean free path, $\lambda = \frac{1}{\sqrt{2}\pi d^{2} n}$ where, n = Number of molecules per unit volume d = Diameter of the molecule As $PV = k_{B}NT$ $n = \frac{N}{V} = \frac{P}{k_{B}T} \quad\therefore \quad\lambda = \frac{1}{\sqrt{2}\pi d^{2} P}$ where, $k_{B} =$ Boltzmann constant $P =$ Pressure of gas $T =$ Absolute temperature of the gas
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