Question

Match the reactions in Group 1 with the catalysts in Group 2

Group 1	Group 2
P) \( C_6H_6 + Cl_2 \;\longrightarrow\; \text{Chlorobenzene + HCl} \)	I) Mixed oxide of Mo and Fe
Q) \( H_2C=CH_2 + \tfrac{1}{2}O_2 \;\longrightarrow\; \text{Ethylene oxide} \)	II) \( V_2O_5 \)
R) \( CH_3OH + \tfrac{1}{2}O_2 \;\longrightarrow\; \text{Formaldehyde + H}_2O \)	III) \( FeCl_3 \)
S) Naphthalene + \( \tfrac{9}{2}O_2 \;\longrightarrow\; \text{Phthalic Anhydride + 2H}_2O + 2CO_2 \)	IV) \( Ag_2O \)

• A. P-III, Q-IV, R-II, S-I
• B. P-III, Q-IV, R-I, S-II
• C. P-IV, Q-II, R-I, S-III
• D. P-IV, Q-III, R-I, S-II

Hint:

Remember common industrial pairs:

Benzene halogenation \(\rightarrow\) Lewis acids (\(\mathrm{FeCl_3/AlCl_3}\)).
Ethylene \(\rightarrow\) ethylene oxide \(\rightarrow\) silver.
Methanol \(\rightarrow\) formaldehyde \(\rightarrow\) Fe–Mo mixed oxides (Formox).
Naphthalene/o\!-xylene \(\rightarrow\) phthalic anhydride \(\rightarrow\) \(\mathrm{V_2O_5}\).

Answer 1

The Correct Option is B

Step 1: Identify catalysts for each reaction

P) Chlorination of benzene is an electrophilic substitution that requires a Lewis acid catalyst such as \(\mathrm{FeCl_3}\). Hence \(P\rightarrow \text{III}\).
Q) Partial oxidation of ethylene to ethylene oxide is industrially carried out on silver catalysts; represented here as \(\mathrm{Ag_2O}\). Hence \(Q\rightarrow \text{IV}\).
R) Oxidation of methanol to formaldehyde (Formox process) uses a mixed oxide catalyst of molybdenum and iron (e.g., \(\mathrm{Fe_2(MoO_4)_3}\)). Hence \(R\rightarrow \text{I}\).
S) Oxidation of naphthalene to phthalic anhydride proceeds over \(\mathrm{V_2O_5}\)-based catalysts. Hence \(S\rightarrow \text{II}\).
Step 2: Consolidate the matching
\[ P-III,\quad Q-IV,\quad R-I,\quad S-II, \] which corresponds to option (B).