Question

Match the rate expressions in LIST-I for the decomposition of X with the corresponding profiles provided in
LIST-II. X_s and k are constants having appropriate units.

LIST I		LIST II
I	rate =\(\frac{k[X]}{Xs+[X]}\) under all possible initial concentration of X	P
II	rate =\(\frac{k[X]}{Xs+[X]}\) where initial concentration of X are much less than Xs​	Q
III	rate =\(\frac{k[X]}{Xs+[X]}\) where initial concentration of X are much higher than Xs​	R
IV	rate =\(\frac{k[X]^2}{Xs+[X]}\),where initial concentration of X is much higher than Xs​	S
		T

 

• A. I → P; II → Q; III → S; IV → T
• B. I → R; II → S; III → S; IV → T
• C. I → P; II → Q; III → Q; IV → R
• D. I → R; II → S; III → Q; IV → R

Answer 1

The Correct Option is A

\((I)\) Rate=\(\frac{k[X]}{Xs+[X]}\)
\( \text{If} [x]→∞⇒ rate →k⇒ order =0\)
\(⇒(I)−(R),(P)\)

\((II)\) \([x]<<x _s ​  ⇒ rate =   ​\frac{k[x]}{x_s} ​  ⇒ order =1\)
\(⇒ (II) −(Q), (T) \)

\((III) [x]>>x _s ​  ⇒ rate =k⇒ order =0\)
\(⇒(III)−(P),(S)\)

\((IV)\) rate =\(\frac{k[X]^2}{Xs+[X]}\)
\([x]>>x _s ​  ⇒ rate =k[x]\)
\(⇒(IV)−(Q),(T)\)