Question

Match the LIST-I with LIST-II \[ \begin{array}{|l|l|} \hline \textbf{LIST I (Liming materials)} & \textbf{LIST II (Neutralizing value of CCE \%)} \\ \hline A. \ \text{Calcium oxide (CaO)} & I. \ 86 \\ B. \ \text{Calcium hydroxide [Ca(OH)$_2$]} & II. \ 108.7 \\ C. \ \text{Dolomite [CaMg(CO$_3$)$_2$]} & III. \ 136 \\ D. \ \text{Basic slag (CaSiO$_3$)} & IV. \ 179 \\ \hline \end{array} \]

• A. A - I, B - II, C - III, D - IV
• B. A - I, B - III, C - II, D - IV
• C. A - IV, B - III, C - II, D - I
• D. A - III, B - IV, C - I, D - II

Hint:

Dolomite is often preferred because it supplies both calcium and magnesium while neutralizing soil acidity.

Answer 1

The Correct Option is A

Step 1: Concept of CCE.
Calcium Carbonate Equivalent (CCE) indicates the neutralizing capacity of liming material compared to pure CaCO$_3$.
Step 2: Matching values.
- Calcium oxide (CaO): Has high reactivity, equivalent neutralizing value ~86. Hence A → I.
- Calcium hydroxide [Ca(OH)$_2$]: More reactive, with CCE around 108.7. Hence B → II.
- Dolomite [CaMg(CO$_3$)$_2$]: CCE ~136 because it contains both Ca and Mg carbonates. Hence C → III.
- Basic slag (CaSiO$_3$): A by-product of steel industry with very high neutralizing value ~179. Hence D → IV.
Step 3: Conclusion.
Correct matching is A - I, B - II, C - III, D - IV.