Question:

Match the following complexes with their number of unpaired electrons:

List-I (Complex) List-II (No. of unpaired electrons) 
A) \([\mathrm{MnCl}_6]^{3-}\) I) 5 
B) \([\mathrm{FeF}_6]^{3-}\) II) 2 
C) \([\mathrm{Mn(CN)}_6]^{3-}\) III) 0 
D) \([\mathrm{Co(C}_2\mathrm{O}_4)_3]^{3-}\) IV) 4 

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Nature of ligand affects crystal field splitting and number of unpaired electrons.
Updated On: Jun 3, 2025
  • A-II, B-IV, C-III, D-I
  • A-IV, B-II, C-I, D-III
  • A-III, B-I, C-IV, D-II
  • A-IV, B-I, C-II, D-III
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The Correct Option is D

Solution and Explanation

- \([\mathrm{MnCl}_6]^{3-}\): high spin, 4 unpaired electrons.
- \([\mathrm{FeF}_6]^{3-}\): high spin, 5 unpaired electrons.
- \([\mathrm{Mn(CN)}_6]^{3-}\): low spin, 2 unpaired electrons.
- \([\mathrm{Co(C}_2\mathrm{O}_4)_3]^{3-}\): low spin, 0 unpaired electrons.
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