In organic reactions, always pay attention to the reagents used and the products formed. Knowing typical reactions of halides with common oxidizing agents can help match the correct answers.
- For \( A \), the reaction \( \text{H}_2\text{C} = \text{CH}_2 \) with \( \text{Hg}_2^{2+}, H_2O \) forms a carboxylic acid, which corresponds to option III, \( \text{HCOOH} \).
- For \( B \), \( \text{CH}_3\text{Cl} \) reacts with \( \text{O}_2 \) in the presence of \( \text{MnO}_2 \), yielding \( \text{CH}_3\text{COOH} \), which corresponds to option IV.
- For \( C \), \( \text{H}_2\text{C} = \text{CH}_2 \) reacts with \( \text{O}_3 \) in the presence of \( \text{Zn} \), and water, forming formic acid \( \text{HCOOH} \), matching with option II.
- For \( D \), \( \text{CH}_3\text{Cl} \) in the presence of \( \text{KMnO}_4 \) and \( H^+ \) forms acetic acid, matching with option I.
Thus, the correct match is option 2.
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Approach Solution -2
To solve the matching, we analyze the reactions in List-I and determine their products in List-II.
A. HC≡CH (Ethyne) + Hg²⁺/H⁺, H₂O
This is the acid-catalyzed hydration of ethyne using Hg²⁺, leading to the formation of acetaldehyde (CH₃CHO) through enol-keto tautomerism.
→ Match: III (CH₃CHO)
B. CH₄ + O₂ (with Mo₂O₃ catalyst and heat)
This is catalytic partial oxidation of methane, producing formaldehyde (HCHO).
→ Match: IV (HCHO)
C. Alkene ozonolysis (with Zn/H₂O)
The double bond of the given alkene (2,3-dimethyl-2-butene) cleaves to give two molecules of CH₃COCH₃ (acetone).
→ Match: II (CH₃COCH₃)
D. CH₃–CH₂–CH₂–CH₃ + KMnO₄/H⁺
Oxidation of alkanes using KMnO₄ cleaves the carbon chain to produce carboxylic acids. Butane forms two molecules of acetic acid (CH₃COOH).
→ Match: I (CH₃COOH)
