Match the electronic configurations in List-I with appropriate metal complex ions in List-II and choose the correct option.
[Atomic Number: Fe = 26, Mn = 25, Co = 27]
List-I List-II (P) \(t^6_{2g} e^0_g\) (1) \( [Fe(H_2O)_6]^{2+}\) (Q) \(t^3_{2g} e^2_g\) (2) \( [Mn(H_2O)_6]^{2+}\) (R) \(e^2t^3_{2}\) (3) \( [Co(NH_3)_6]^{3+}\) (S) \(t^4_{2g} e^2_g\) (4) \([FeCl_4]^-\) (5) \( [CoCl_4]^{2-}\)
[Atomic Number: Fe = 26, Mn = 25, Co = 27]
| List-I | List-II | ||
| (P) | \(t^6_{2g} e^0_g\) | (1) | \( [Fe(H_2O)_6]^{2+}\) |
| (Q) | \(t^3_{2g} e^2_g\) | (2) | \( [Mn(H_2O)_6]^{2+}\) |
| (R) | \(e^2t^3_{2}\) | (3) | \( [Co(NH_3)_6]^{3+}\) |
| (S) | \(t^4_{2g} e^2_g\) | (4) | \([FeCl_4]^-\) |
| (5) | \( [CoCl_4]^{2-}\) |
P →1; Q→ 4; R →2; S →3
P →1; Q→ 2; R →4; S →5
P →3; Q→ 2; R →5; S →1
P →3; Q→ 2; R →4; S →1
The Correct Option is D
Solution and Explanation
- Fe (Iron) has an atomic number of 26.
- Mn (Manganese) has an atomic number of 25.
- Co (Cobalt) has an atomic number of 27.
- (P) \(t^6_{2g} e^0_g\): This configuration suggests a complete \(t_{2g}\) level with no electrons in the \(e_g\) orbital, indicating a low-spin state. Since the low-spin configuration is more common with strong-field ligands, it matches with \([Co(NH_3)_6]^{3+}\) because NH\(_3\) is a strong-field ligand. Thus, P → (3).
- (Q) \(t^3_{2g} e^2_g\): This configuration indicates a total of 5 d-electrons distributed among \(t_{2g}\) and \(e_g\) orbitals. This corresponds to the 5 d-electrons of \([Mn(H_2O)_6]^{2+}\) which is a common high-spin state for Mn\(^2+\) with weak-field ligand H\(_2\)O. Thus, Q → (2).
- (R) \(e^2t^3_{2}\): This configuration indicates that the \(e\) orbitals are filled with 2 electrons, and is commonly seen with \([FeCl_4]^-\), where Cl\(^-\) is a weak-field ligand leading to a high-spin configuration. Thus, R → (4).
- (S) \(t^4_{2g} e^2_g\): This suggests 6 d-electrons, which matches with \([Fe(H_2O)_6]^{2+}\), because Fe\(\) electronic configuration in this complex shows high-spin with a weak-field ligand like H\(_2\)O. Thus, S → (1).
P → 3; Q → 2; R → 4; S → 1
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Concepts Used:
Stoichiometry
Stoichiometry is founded on the law of conservation of mass where the total mass of the reactants equals the total mass of the products, leading to the insight that the relations among quantities of reactants and products typically form a ratio of positive integers. This means that if the amounts of the separate reactants are known, then the amount of the product can be calculated. Conversely, if one reactant has a known quantity and the quantity of the products can be empirically determined, then the amount of the other reactants can also be calculated.
Stoichiometry helps us determine how much substance is needed or is present. Things that can be measured are;
- Reactants and Products mass
- Molecular weight
- Chemical equations
- Formulas
Stoichiometric Coefficient
The Stoichiometric coefficient of any given component is the number of molecules and/or formula units that participate in the reaction as written.
Mole Ratios
The mass of one mole of a substance in grams is called molar mass. The molar mass of one mole of a substance is numerically equal to the atomic/molecular formula mass.