Question

Match List-I with the List-II

List-I (Compound / Species)	List-II (Shape / Geometry)
(A) \(SF_4\)	(I) Tetrahedral
(B) \(BrF_3\)	(II) Pyramidal
(C) \(BrO_{3}^{-}\)	(III) See saw
(D) \(NH^{+}_{4}\)	(IV) Bent T-shape

Choose the correct answer from the options given below:

• A. A-II, B-III, C-I, D-IV
• B. A-III, B-IV, C-II, D-I
• C. A-II, B-IV, C-III, D-I
• D. A-III, B-II, C-IV, D-I

Answer 1

The Correct Option is B

(A) SF$_4$: The sulfur atom in SF$_4$ undergoes sp$^3$d hybridization, resulting in a see-saw geometry.
(B) BrF$_3$: Bromine in BrF$_3$ exhibits sp$^3$d hybridization with two lone pairs, resulting in a bent T-shape geometry.
(C) BrO$_3^-$: The bromine atom in BrO$_3^-$ is sp$^3$ hybridized, resulting in a pyramidal geometry.
(D) NH$_4^+$: The nitrogen atom in NH$_4^+$ undergoes sp$^3$ hybridization, forming a tetrahedral geometry.