Question:

Match List I with List II
List IList II
A.\(\frac{d^2y}{dx^2}+(\frac{dy}{dx})^{\frac{1}{2}}+x^{\frac{1}{2}}\)I.order 2, degree 1
B.\(\frac{dy}{dx}=\frac{x^{\frac{1}{2}}}{y^{\frac{1}{2}}(1+x)^{\frac{1}{2}}}\)II.order 2, degree not defined
C.\(\frac{d^2y}{dx^2}=\cos3x+\sin3x\)III.order 2, degree 4
D.\(\frac{d^2y}{dx^2}+2\frac{dy}{dx}+y=\log(\frac{dy}{dx})\)IV.order 1, degree 2
Choose the correct answer from the options given below :

Updated On: May 11, 2025
  • A-I, B-II, C-III, D-IV
  • A-III, B-IV, C-I, D-II
  • A-III, B-II, C-IV, D-I
  • A-III, B-I, C-II, D-IV
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The Correct Option is B

Solution and Explanation

To solve the problem of matching equations in List I with their respective orders and degrees in List II, we need to analyze each differential equation:
  • Equation A: \(\frac{d^2y}{dx^2}+(\frac{dy}{dx})^{\frac{1}{2}}+x^{\frac{1}{2}}\)
    • Order: 2, as the highest derivative is \(\frac{d^2y}{dx^2}\).
    • Degree is not defined because \((\frac{dy}{dx})^{\frac{1}{2}}\) involves a fractional power of a derivative.
  • Equation B: \(\frac{dy}{dx}=\frac{x^{\frac{1}{2}}}{y^{\frac{1}{2}}(1+x)^{\frac{1}{2}}}\)
    • Order: 1, as the highest order derivative is \(\frac{dy}{dx}\).
    • Degree: 2, since the equation can be expressed without any fractional powers on the derivative, after some manipulation.
  • Equation C: \(\frac{d^2y}{dx^2}=\cos3x+\sin3x\)
    • Order: 2, as the highest derivative is \(\frac{d^2y}{dx^2}\).
    • Degree: 1, because all terms on the right don't involve derivatives.
  • Equation D: \(\frac{d^2y}{dx^2}+2\frac{dy}{dx}+y=\log(\frac{dy}{dx})\)
    • Order: 2, as the highest derivative is \(\frac{d^2y}{dx^2}\).
    • Degree is not defined because \(\log(\frac{dy}{dx})\) is a non-polynomial term involving a derivative.
Matching the characteristics with List II gives us:
  • A: Order 2, Degree not defined - Matches with III.
  • B: Order 1, Degree 2 - Matches with IV.
  • C: Order 2, Degree 1 - Matches with I.
  • D: Order 2, Degree not defined - Matches with II.
Thus, the correct mapping is: A-III, B-IV, C-I, D-II. Therefore, the correct answer is:
A-III, B-IV, C-I, D-II
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