Match List I with List II List I List II $A.\ [1 + (\frac{dy}{dx})^2] = \frac{d^2y}{dx^2}$ I. order 2, degree 3 $B. \ (\frac{d^3y}{dx^2})^2 - 3\frac{d^2y}{dx^2} + 2(\frac{dy}{dx})^4 = y^4$ II. order 2, degree 1 $C. \ (\frac{dy}{dx})^2 + (\frac{d^2y}{dx^2})^3 = 0$ III. order 1, degree 2 $D.\ (\frac{dy}{dx})^2 + 6y^3 = 0$ IV. order 3, degree 2 Choose the correct answer from the options given below:

Question

cdquestions Admin · Accepted Answer

The correct option is (D): A-II, B-IV, C-I, D-III

Answer

А-І, В-II, C-IV, D-II

Answer

А-III, В-I, C-II, D-IV

Answer

A-IV, B-II, C-III, D-I

Answer

A-II, B-IV, C-I, D-III

The Correct Option is D

Solution and Explanation

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List I	List II
\(A.\ [1 + (\frac{dy}{dx})^2] = \frac{d^2y}{dx^2}\)	I. order 2, degree 3
\(B. \ (\frac{d^3y}{dx^2})^2 - 3\frac{d^2y}{dx^2} + 2(\frac{dy}{dx})^4 = y^4\)	II. order 2, degree 1
\(C. \ (\frac{dy}{dx})^2 + (\frac{d^2y}{dx^2})^3 = 0\)	III. order 1, degree 2
\(D.\ (\frac{dy}{dx})^2 + 6y^3 = 0\)	IV. order 3, degree 2