List-I | List-II | ||
(A) | Isothermal process | (I) | No heat exchange |
(B) | Isochoric process | (II) | Carried out at constant temperature |
(C) | Isobaric process | (III) | Carried out at constant volume |
(D) | Adiabatic process | (IV) | Carried out at constant pressure |
Step 1: Recall the Definitions of Thermodynamic Processes
Isothermal Process
The temperature remains constant, meaning \( \Delta T = 0 \). The equation used is:
$$ PV = \text{constant} $$
This process is carried out at constant temperature (II).
Isochoric Process
The volume remains constant, meaning \( \Delta V = 0 \), so no work is done:
$$ W = 0 $$
This process is carried out at constant volume (III).
Isobaric Process
The pressure remains constant, meaning \( \Delta P = 0 \), and the work done is:
$$ W = P \Delta V $$
This process is carried out at constant pressure (IV).
Adiabatic Process
No heat exchange occurs, meaning \( Q = 0 \), and the equation governing the process is:
$$ PV^\gamma = \text{constant} $$
This process has no heat exchange (I).
Step 2: Match the Processes with Their Respective Conditions
Step 3: Conclusion
The correct answer is: Option (4) A-II, B-III, C-IV, D-I.
A bob of heavy mass \(m\) is suspended by a light string of length \(l\). The bob is given a horizontal velocity \(v_0\) as shown in figure. If the string gets slack at some point P making an angle \( \theta \) from the horizontal, the ratio of the speed \(v\) of the bob at point P to its initial speed \(v_0\) is :