Question:

Match List-I with List-II

List-IList-II
(A) \( f(x) = |x| \)(I) Not differentiable at \( x = -2 \) only
(B) \( f(x) = |x + 2| \)(II) Not differentiable at \( x = 0 \) only
(C) \( f(x) = |x^2 - 4| \)(III) Not differentiable at \( x = 2 \) only
(D) \( f(x) = |x - 2| \)(IV) Not differentiable at \( x = 2, -2 \) only


Choose the correct answer from the options given below:

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To quickly find points of non-differentiability for an absolute value function f(x) = |g(x)|, solve the equation g(x) = 0. The roots of this equation are the candidates for points where the function is not differentiable, especially if g'(x) is not zero at those roots.
Updated On: Sep 9, 2025
  • (A) - (I), (B) - (II), (C) - (III), (D) - (IV)
  • (A) - (II), (B) - (I), (C) - (IV), (D) - (III)
  • (A) - (II), (B) - (I), (C) - (III), (D) - (IV)
  • (A) - (IV), (B) - (III), (C) - (II), (D) - (I)
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The Correct Option is B

Solution and Explanation

Step 1: Understanding the Concept:
A function of the form f(x) = |g(x)| is generally not differentiable at the points where g(x) = 0, because these points often correspond to sharp corners or "cusps" in the graph. We need to find these points for each function in List-I.
Step 3: Detailed Explanation:
Let's analyze each function in List-I.
(A) f(x) = |x|
The function is not differentiable where the expression inside the absolute value is zero.
\(x = 0\).
So, f(x) = |x| is not differentiable at x = 0 only. This matches with (II).
(B) f(x) = |x + 2|
Set the expression inside the absolute value to zero.
\(x + 2 = 0 \implies x = -2\).
So, f(x) = |x + 2| is not differentiable at x = -2 only. This matches with (I).
(C) f(x) = $|x^2 - 4|$
Set the expression inside the absolute value to zero.
\(x^2 - 4 = 0 \implies (x - 2)(x + 2) = 0\).
The solutions are x = 2 and x = -2.
So, f(x) = $|x^2 - 4|$ is not differentiable at x = 2 and x = -2. This matches with (IV).
(D) f(x) = |x - 2|
Set the expression inside the absolute value to zero.
\(x - 2 = 0 \implies x = 2\).
So, f(x) = |x - 2| is not differentiable at x = 2 only. This matches with (III).
Step 4: Final Answer:
The correct matching is:
(A) $\rightarrow$ (II)
(B) $\rightarrow$ (I)
(C) $\rightarrow$ (IV)
(D) $\rightarrow$ (III)
This corresponds to option (2).
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