List I (Reagents Used) | List II (Compound with Functional group detected) | ||
A | Alkaline solution of copper sulphate and sodium citrate | I | ![]() |
B | Neutral FeCl3 solution | II | ![]() |
C | Alkaline chloroform solution | III | ![]() |
D | Potassium iodide and sodium hypochlorite | IV | ![]() |
Choose the correct answer from the options given below :
A: Alkaline solution of copper sulphate and sodium citrate detects aldehydes. The aldehyde reacts to form a reddish-brown precipitate of Cu$_2$O.
B: Neutral FeCl$_3$ solution is used for detecting phenolic groups. Phenols give a characteristic color (violet or blue).
C: Alkaline chloroform solution (Haloform test) detects the presence of a methyl ketone or a methyl group adjacent to a hydroxyl group.
D: Potassium iodide and sodium hypochlorite (Iodoform test) confirms alcohol groups (-CH$_3$OH). \end{itemize}
Match List-I with List-II:
Let \[ I(x) = \int \frac{dx}{(x-11)^{\frac{11}{13}} (x+15)^{\frac{15}{13}}} \] If \[ I(37) - I(24) = \frac{1}{4} \left( b^{\frac{1}{13}} - c^{\frac{1}{13}} \right) \] where \( b, c \in \mathbb{N} \), then \[ 3(b + c) \] is equal to:
For the thermal decomposition of \( N_2O_5(g) \) at constant volume, the following table can be formed, for the reaction mentioned below: \[ 2 N_2O_5(g) \rightarrow 2 N_2O_4(g) + O_2(g) \] Given: Rate constant for the reaction is \( 4.606 \times 10^{-2} \text{ s}^{-1} \).