List I (Reagents Used) | List II (Compound with Functional group detected) | ||
A | Alkaline solution of copper sulphate and sodium citrate | I | ![]() |
B | Neutral FeCl3 solution | II | ![]() |
C | Alkaline chloroform solution | III | ![]() |
D | Potassium iodide and sodium hypochlorite | IV | ![]() |
Choose the correct answer from the options given below :
A: Alkaline solution of copper sulphate and sodium citrate detects aldehydes. The aldehyde reacts to form a reddish-brown precipitate of Cu$_2$O.
B: Neutral FeCl$_3$ solution is used for detecting phenolic groups. Phenols give a characteristic color (violet or blue).
C: Alkaline chloroform solution (Haloform test) detects the presence of a methyl ketone or a methyl group adjacent to a hydroxyl group.
D: Potassium iodide and sodium hypochlorite (Iodoform test) confirms alcohol groups (-CH$_3$OH). \end{itemize}
The alkali metal with the lowest E M- M+ (V) is X and the alkali metal with highest E M- M+ is Y. Then X and Y are respectively:
Let A be a 3 × 3 matrix such that \(\text{det}(A) = 5\). If \(\text{det}(3 \, \text{adj}(2A)) = 2^{\alpha \cdot 3^{\beta} \cdot 5^{\gamma}}\), then \( (\alpha + \beta + \gamma) \) is equal to:
Let \( \alpha, \beta \) be the roots of the equation \( x^2 - ax - b = 0 \) with \( \text{Im}(\alpha) < \text{Im}(\beta) \). Let \( P_n = \alpha^n - \beta^n \). If \[ P_3 = -5\sqrt{7}, \quad P_4 = -3\sqrt{7}, \quad P_5 = 11\sqrt{7}, \quad P_6 = 45\sqrt{7}, \] then \( |\alpha^4 + \beta^4| \) is equal to: