Match List I with List II LIST I LIST II A . Range of y=cosec -1 x I . R-(-1, 1) B . Domain of sec -1 x II . (0, π) C . Domain of sin -1 x III . [-1, 1] D . Range of y=cot -1 x IV . $[\frac{-π}{2},\frac{π}{2}]$ -{0} Choose the correct answer from the options given below:

Question

Match List I with List II LIST I   LIST II A . Range of y=cosec -1 x I . R-(-1, 1) B . Domain of sec -1 x II . (0, π) C . Domain of sin -1 x III . [-1, 1] D . Range of y=cot -1 x IV . $[\frac{-π}{2},\frac{π}{2}]$ -{0} Choose the correct answer from the options given below:

cdquestions Admin · Accepted Answer

The correct option is (B):(A)-(IV), (B)-(I), (C)-(III), (D)-(II)

Answer

(A)-(I), (B)-(II), (C)-(IV), (D)-(III)

Answer

(A)-(IV), (B)-(I), (C)-(III), (D)-(II)

Answer

(А)-(III), (B)-(IV), (C)-(II), (D)-(I)

Answer

(A)-(II), (B)-(III), (C)-(I), (D)-(IV)

	LIST I		LIST II
A.	Range of y=cosec^-1x	I.	R-(-1, 1)
B.	Domain of sec^-1x	II.	(0, π)
C.	Domain of sin^-1x	III.	[-1, 1]
D.	Range of y=cot^-1x	IV.	\([\frac{-π}{2},\frac{π}{2}]\)-{0}

Match List I with List II
LIST I LIST II
A. Range of y=cosec^-1x I. R-(-1, 1)
B. Domain of sec^-1x II. (0, π)
C. Domain of sin^-1x III. [-1, 1]
D. Range of y=cot^-1x IV. \([\frac{-π}{2},\frac{π}{2}]\)-{0}
Choose the correct answer from the options given below:

The Correct Option is B

Solution and Explanation

Top Questions on Relations and Functions

Questions Asked in CUET exam

Match List I with List II LIST I LIST IIA.Range of y=cosec-1xI.R-(-1, 1)B.Domain of sec-1xII.(0, π)C.Domain of sin-1xIII.[-1, 1]D.Range of y=cot-1xIV.\([\frac{-π}{2},\frac{π}{2}]\)-{0}Choose the correct answer from the options given below:

The Correct Option is B

Solution and Explanation

Top Questions on Relations and Functions

Questions Asked in CUET exam

Match List I with List II
LIST I LIST II
A. Range of y=cosec^-1x I. R-(-1, 1)
B. Domain of sec^-1x II. (0, π)
C. Domain of sin^-1x III. [-1, 1]
D. Range of y=cot^-1x IV. \([\frac{-π}{2},\frac{π}{2}]\)-{0}
Choose the correct answer from the options given below: