Question

Match List - I with List - II : 

Choose the most appropriate answer from the options given 
 

• A. (a)-(ii), (b)-(i), (c)-(ii), (d)-(iii), (e)-(iii)
• B. (a)-(ii), (b)-(iii), (c)-(ii), (d)-(i), (e)-(iii)
• C. (a)-(ii), (b)-(iii), (c)-(ii), (d)-(i), (e)-(iii)
• D. (a)-(ii), (b)-(ii), (c)-(iii), (d)-(ii), (e)-(iii)

Hint:

Remember the trends in the periodic table for hydroxide basicity. It generally increases down a group and decreases across a period. Also, memorize key amphoteric hydroxides like Be(OH)$_2$, Al(OH)$_3$, Zn(OH)$_2$, Sn(OH)$_2$, Pb(OH)$_2$.

Answer 1

The Correct Option is B

Let's determine the nature of each hydroxide in List-I.
(a) NaOH: Sodium hydroxide is a classic strong alkali, a compound of a Group 1 metal. It is strongly Basic. So, (a) matches with (ii).
(b) Be(OH)$_2$: Beryllium hydroxide is an exception in Group 2. Due to the small size and high charge density of Be$^{2+}$, it is Amphoteric, meaning it can react with both acids and bases. So, (b) matches with (iii).
(c) Ca(OH)$_2$: Calcium hydroxide (slaked lime) is a strong base, typical for a Group 2 metal hydroxide. So, (c) matches with (ii).
(d) B(OH)$_3$: Boron hydroxide is better known as Boric Acid. It is a weak Lewis acid, accepting an OH$^-$ ion from water rather than donating a proton. So, (d) matches with (i).
(e) Al(OH)$_3$: Aluminium hydroxide is a well-known Amphoteric hydroxide, reacting with acids to form Al$^{3+}$ salts and with strong bases to form aluminates like [Al(OH)$_4$]$^-$. So, (e) matches with (iii).
The complete matching is: (a)-(ii), (b)-(iii), (c)-(ii), (d)-(i), (e)-(iii).
This corresponds to options (B) and (C) which are identical in the provided image. We select (B).