Step 1: Understanding the Concept:
This question tests the knowledge of different types of gene interactions (epistasis) and their characteristic modified Mendelian F2 dihybrid ratios. The standard dihybrid ratio is 9:3:3:1.
Step 2: Detailed Explanation:
Let's match each type of gene interaction with its resulting F2 ratio:
A. Complementary gene action: Both dominant genes (e.g., A and B) are required to produce a particular phenotype. The absence of either dominant gene results in a different phenotype. Genotypes A_B_ produce one phenotype, while A_bb, aaB_, and aabb produce another. This combines the 3, 3, and 1 parts of the ratio, leading to a 9:7 ratio. This matches IV.
B. Supplementary gene action (Recessive Epistasis): A recessive allele at one locus (e.g., aa) masks the expression of alleles at another locus. For example, A_B_ (phenotype 1), A_bb (phenotype 2), but aaB_ and aabb are both phenotype 3. This combines the 3 and 1 parts, leading to a 9:3:4 ratio. This matches III.
C. Inhibitory gene action: A dominant allele at one locus (the inhibitor gene, I) prevents the expression of a dominant allele at another locus. For example, I_C_ and I_cc are one phenotype (e.g., white), iiC_ is the second phenotype (colored), and iicc is also the first phenotype (white). This combines the 9, 3, and 1 parts, leading to a 13:3 ratio. This matches II.
D. Masking gene action (Dominant Epistasis): A dominant allele at one locus (e.g., A) masks the expression of alleles at another locus. For example, A_B_ and A_bb produce one phenotype, aaB_ produces a second, and aabb produces a third. This combines the 9 and 3 parts, leading to a 12:3:1 ratio. This matches I.
Step 3: Final Answer:
The correct matching is A-IV, B-III, C-II, D-I.