Question

Match List-I with List-II.

\[ \begin{array}{|l|l|} \hline \textbf{LIST I} & \textbf{LIST II} \\ \hline A.\; \text{Pūrṇakāśyapa} & I.\; \text{Akṛtavāda} \\ \hline B.\; \text{Ajita Keśakambala} & II.\; \text{Akriyāvāda} \\ \hline C.\; \text{Prakṛdha Kātyāyana} & III.\; \text{Bhautikavāda} \\ \hline D.\; \text{Sañjaya Velaṭṭhiputra} & IV.\; \text{Aniścitatāvāda} \\ \hline \end{array} \]

• (A) - (II), (B) - (III), (C) - (I), (D) - (IV)
• (A) - (I), (B) - (III), (C) - (IV), (D) - (II)
• (A) - (III), (B) - (IV), (C) - (II), (D) - (I)
• (A) - (IV), (B) - (I), (C) - (III), (D) - (II)

Hint:

Remember Ajita Keśakambala = materialist (Bhautikavāda).

Answer 1

The Correct Option is B

Step 1: Identifying ancient teachers.
- Pūrṇakāśyapa ne Akṛtavāda (karma kā phal nahīṁ hotā) kā siddhānta diyā.
- Ajita Keśakambala ne Bhautikavāda (materialism) ko samarthan diyā.
- Prakṛdha Kātyāyana ne Aniścitatāvāda (uncertainty doctrine) kā ullekh kiyā.
- Sañjaya Velaṭṭhiputra ne Akriyāvāda (action is ineffective) ko mānā.
Step 2: Matching.
- A → I ✔
- B → III ✔
- C → IV ✔
- D → II ✔
Step 3: Conclusion.
Sahi uttar hai (2).