Question

Match isostructural species in Column I with Column II.

• A. A$\rightarrow$P, B$\rightarrow$S, C$\rightarrow$R, D$\rightarrow$Q
• B. A$\rightarrow$P, B$\rightarrow$Q, C$\rightarrow$R, D$\rightarrow$S
• C. A$\rightarrow$S, B$\rightarrow$R, C$\rightarrow$Q, D$\rightarrow$P
• D. A$\rightarrow$S, B$\rightarrow$Q, C$\rightarrow$R, D$\rightarrow$P

Hint:

To identify isostructural species quickly, count {bond pairs + lone pairs} on the central atom and apply VSEPR geometry.

Answer 1

The Correct Option is A

Concept:
Isostructural species have the same molecular geometry
, which is determined by the number of bonding pairs and lone pairs around the central atom according to VSEPR theory.
Step 1: Determine Geometry of Column-I Species
(A) XeF$_2$:


AX$_2$E$_3$ type
Geometry: Linear

(B) XeOF$_4$:


AX$_5$E type
Geometry: Square pyramidal

(C) XeO$_2$F$_2$:


AX$_4$E type
Geometry: Seesaw

(D) XeO$_3$:


AX$_3$E type
Geometry: Trigonal pyramidal


Step 2: Match with Column-II Species


I$_3^-$ $\rightarrow$ Linear $\Rightarrow$ matches with XeF$_2$ (A$\rightarrow$P)
BrF$_5$ $\rightarrow$ Square pyramidal $\Rightarrow$ matches with XeOF$_4$ (B$\rightarrow$S)
SF$_4$ $\rightarrow$ Seesaw $\Rightarrow$ matches with XeO$_2$F$_2$ (C$\rightarrow$R)
NH$_3$ $\rightarrow$ Trigonal pyramidal $\Rightarrow$ matches with XeO$_3$ (D$\rightarrow$Q)

Final Conclusion:
\[ \boxed{\text{A}\rightarrow\text{P},\ \text{B}\rightarrow\text{S},\ \text{C}\rightarrow\text{R},\ \text{D}\rightarrow\text{Q}} \]