Question:

M with unity coupling coefficient. The stored magnetic energy of the coupled circuits is minimum at which of the following values of \( \frac{I_1}{I_2} \)?

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In coupled circuits, the stored magnetic energy is minimized when the current ratio \( \frac{I_1}{I_2} \) is equal to \( \frac{-M}{L_1} \).
Updated On: Feb 14, 2025
  • \( \frac{-M}{L_2} \)
  • \( \frac{-L_2}{M} \)
  • \( \frac{-M}{L_1} \)
  • \( \frac{-L_1}{M} \)
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The Correct Option is C

Solution and Explanation

Step 1: For coupled circuits, the magnetic energy is a function of the mutual inductance \( M \) and the inductances \( L_1 \) and \( L_2 \). The energy stored in the magnetic field of the coupled system is minimized when the current ratio \( \frac{I_1}{I_2} \) reaches a specific value determined by the system parameters.
Step 2: The energy is minimum when the current ratio is \( \frac{-M}{L_1} \), as this corresponds to the condition where the magnetic coupling is at its most efficient, minimizing the stored energy.
Thus, the correct answer is \( \frac{-M}{L_1} \).
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