>
Exams
>
Mathematics
>
Sequences and Series
>
look at the series 1224 612 204 102 34 which one o
Question:
Look at the series : 1224, 612, 204, 102, 34,…. which one of the following numbers should come next in the series?
CUET (PG) - 2023
CUET (PG)
Updated On:
May 2, 2024
18
17
16
15
Hide Solution
Verified By Collegedunia
The Correct Option is
B
Solution and Explanation
The correct option is(B): 17
Download Solution in PDF
Was this answer helpful?
0
0
Top Questions on Sequences and Series
If \[ a_n=(2n^2-n+2)(n!) , \] then \[ \sum_{n=1}^{20} a_n \] is equal to:
JEE Main - 2026
Mathematics
Sequences and Series
View Solution
If sum of first 4 terms of an A.P. is 6 and sum of first 6 terms is 4, then sum of first 12 terms of an A.P. is
JEE Main - 2026
Mathematics
Sequences and Series
View Solution
If \(a_1 = 1\) and for all \(n \ge 1\), \[ a_{n+1} = \frac{1}{2}a_n + \frac{n^2 - 2n - 1}{n^2 (n+1)^2}, \] then the value of \[ \sum_{n=1}^{\infty} \left( a_n - \frac{2}{n^2} \right) \] is equal to:
JEE Main - 2026
Mathematics
Sequences and Series
View Solution
Let \( f(x) = \lim_{n \to \infty} \left( \frac{1}{n^3} \sum_{k=1}^{n} \left\lfloor \frac{k^2}{3^x} \right\rfloor \right) \), where \( \left\lfloor . \right\rfloor \) denotes the greatest integer function, then \( 12 \sum_{j=1}^{\infty} f(j) \) is equal to:
JEE Main - 2026
Mathematics
Sequences and Series
View Solution
If \( \sum_{k=1}^{n} a_k = \alpha n^2 + \beta n \) and \( a_{10} = 59,\; a_6 = 7a_1 \), then find \( \alpha + \beta \):
JEE Main - 2026
Mathematics
Sequences and Series
View Solution
View More Questions
Questions Asked in CUET PG exam
Lakulish sect is related to:
CUET (PG) - 2025
Ancient History
View Solution
One term in the given number series is wrong. Find out the wrong term.
CUET (PG) - 2025
Number Series
View Solution
Match List-I with List-II
Choose the correct answer from the options given below:
CUET (PG) - 2025
Microbiology
View Solution
HPV is responsible mainly for:
CUET (PG) - 2025
Microbiology
View Solution
Which bacteria is called the DNA repair champion
CUET (PG) - 2025
Microbiology
View Solution
View More Questions