The logarithm of 2, \( \log 2 \), is an irrational number. This can be shown because \( \log 2 \) cannot be expressed as a fraction of two integers. The value of \( \log 2 \) (in base 10) is approximately 0.3010, and it cannot be expressed exactly as a rational number.
Therefore, the correct answer is that \( \log 2 \) is an irrational number.