List I | List II | ||
(P) | ![]() | (1) | ![]() |
(Q) | ![]() | (2) | ![]() |
(R) | ![]() | (3) | ![]() |
(S) | ![]() | (4) | ![]() |
(5) | ![]() |
Step 1: Understanding the Reaction Sequences
Step 2: Conclusion
Thus, the correct answer is (C) P-3, Q-5, R-4, S-1.
To solve the problem, we need to analyze each reaction sequence and match it with the correct phenolic compound product.
1. For (P):
- Sulfonation of benzene sulfonic acid followed by nitration.
- The sulfonic group is replaced by hydroxyl (via molten NaOH and acidification).
- Final product is Trinitrophenol.
- Corresponds to structure (3).
2. For (Q):
- Nitration of nitrobenzene, reduction, diazotization, and further nitration.
- Final product is 2,4,6-trinitrophenol (picric acid).
- Corresponds to structure (5).
3. For (R):
- Nitration of hydroquinone (1,4-dihydroxybenzene).
- Final product is 2,5-dinitrohydroquinone.
- Corresponds to structure (4).
4. For (S):
- Multiple steps starting from toluene, oxidation, nitration, bromination, diazotization.
- Final product is 2,4-dinitrophenol.
- Corresponds to structure (1).
Final Matching:
P - 3, Q - 5, R - 4, S - 1
Final Answer:
Option (C)
The order of acidity of the following compounds is:
(i) o-Nitrophenol
(ii) Phenol
(iii) o-Cresol
(iv) Ethanol
Given below are two statements:
Statement I: Dimethyl ether is completely soluble in water. However, diethyl ether is soluble in water to a very small extent.
Statement II: Sodium metal can be used to dry diethyl ether and not ethyl alcohol.
In the light of the given statements, choose the correct answer from the options given below:
Figure 1 shows the configuration of main scale and Vernier scale before measurement. Fig. 2 shows the configuration corresponding to the measurement of diameter $ D $ of a tube. The measured value of $ D $ is:
The center of a disk of radius $ r $ and mass $ m $ is attached to a spring of spring constant $ k $, inside a ring of radius $ R>r $ as shown in the figure. The other end of the spring is attached on the periphery of the ring. Both the ring and the disk are in the same vertical plane. The disk can only roll along the inside periphery of the ring, without slipping. The spring can only be stretched or compressed along the periphery of the ring, following Hooke’s law. In equilibrium, the disk is at the bottom of the ring. Assuming small displacement of the disc, the time period of oscillation of center of mass of the disk is written as $ T = \frac{2\pi}{\omega} $. The correct expression for $ \omega $ is ( $ g $ is the acceleration due to gravity):