List-I | List-II | ||
|---|---|---|---|
| I | ![]() | P | Final image is formed at 7.5 cm on the right side of lens 2. |
| II | ![]() | Q | Final image is formed at 60.0 cm on the right side of lens 2 |
| III | ![]() | R | Final image is formed at 30.0 cm on the left side of lens 2. |
| IV | ![]() | S | Final image is formed at 6.0 cm on the right side of lens 2. |
| T | Final image is formed at 30.0 cm on the right side of lens 2. | ||
(I) → P; (II) → R; (III) → Q; (IV) → T
(I) → Q; (II) → P; (III) → T; (IV) → S
(I) → P; (II) → T; (III) → R; (IV) → Q
(I) → T; (II) → S; (III) → Q; (IV) → R
For the first lens (focal length \( f_1 = +15 \, \text{cm} \)), use the lens formula:
\[ \frac{1}{f} = \frac{1}{v} - \frac{1}{u} \] where \( u = -20 \, \text{cm} \) (object distance) and \( f = 15 \, \text{cm} \). Solving this gives the image position for the first lens, which is further used to find the image for the second lens (focal length \( f_2 = +10 \, \text{cm} \)). After performing the calculations, the final image position is found at \( 7.5 \, \text{cm} \) on the right side of the second lens, matching with option P.The correct match of options is:
The correct answer is Option A: (I) - P, (II) - Q, (III) - R, (IV) - T.
As shown in the figures, a uniform rod $ OO' $ of length $ l $ is hinged at the point $ O $ and held in place vertically between two walls using two massless springs of the same spring constant. The springs are connected at the midpoint and at the top-end $ (O') $ of the rod, as shown in Fig. 1, and the rod is made to oscillate by a small angular displacement. The frequency of oscillation of the rod is $ f_1 $. On the other hand, if both the springs are connected at the midpoint of the rod, as shown in Fig. 2, and the rod is made to oscillate by a small angular displacement, then the frequency of oscillation is $ f_2 $. Ignoring gravity and assuming motion only in the plane of the diagram, the value of $\frac{f_1}{f_2}$ is:
The reaction sequence given below is carried out with 16 moles of X. The yield of the major product in each step is given below the product in parentheses. The amount (in grams) of S produced is ____. 
Use: Atomic mass (in amu): H = 1, C = 12, O = 16, Br = 80
Let $ a_0, a_1, ..., a_{23} $ be real numbers such that $$ \left(1 + \frac{2}{5}x \right)^{23} = \sum_{i=0}^{23} a_i x^i $$ for every real number $ x $. Let $ a_r $ be the largest among the numbers $ a_j $ for $ 0 \leq j \leq 23 $. Then the value of $ r $ is ________.
Let $ \mathbb{R} $ denote the set of all real numbers. Then the area of the region $$ \left\{ (x, y) \in \mathbb{R} \times \mathbb{R} : x > 0, y > \frac{1}{x},\ 5x - 4y - 1 > 0,\ 4x + 4y - 17 < 0 \right\} $$ is
Lenses that are made by combining two spherical transparent surfaces are called spherical lenses. In general, there are two kinds of spherical lenses. Lenses that are made by joining two spherical surfaces that bulge outward are convex lenses, whereas lenses that are made by joining two spherical surfaces that curve inward are concave lenses.