LIST-I | LIST-II | ||
|---|---|---|---|
| I | \(\text{H}_2\text{O}_2\) | P | \(\text{Mg(HCO}_3\text{)}_2 + \text{Ca(OH)}_2 \rightarrow \) |
| II | \(\mathrm{Mg(OH)_2}\) | Q | \(\text{BaO}_2 + \text{H}_2\text{SO}_4 \rightarrow \) |
| III | \(\text{BaCl}_2\) | R | \(\text{Ca(OH)}_2 + \text{MgCl}_2 \) |
| IV | \(\text{CaCO}_3\) | S | \(\text{BaO}_2 + 2\text{HCl} \rightarrow\) |
| T | \(\text{Ca(HCO}_3\text{)}_2 + 2\text{Ca(OH)}_2 \rightarrow \) | ||
I → Q; II → P; III → S; IV → R
I → T; II → P; III → Q; IV → R
I → T; II → R; III → Q; IV → P
I → Q; II → R; III → S; IV → P
The formation of hydrogen peroxide (\( \text{H}_2\text{O}_2 \)) happens by the reaction between \( \text{BaO}_2 \) and \( \text{H}_2\text{SO}_4 \).
This corresponds to reaction Q.
The formation of magnesium hydroxide (\( \text{Mg(OH)}_2 \)) occurs when \( \text{Ca(OH)}_2 \) reacts with \( \text{MgCl}_2 \).
This corresponds to reaction R.
Barium chloride (\( \text{BaCl}_2 \)) reacts with hydrochloric acid to form barium peroxide (\( \text{BaO}_2 \)), which corresponds to reaction S.
Calcium carbonate (\( \text{CaCO}_3 \)) is formed when \( \text{Mg(HCO}_3\text{)}_2 \) reacts with \( \text{Ca(OH)}_2 \), corresponding to reaction P.
The correct matches are:
The correct option is A: I → Q; II → R; III → S; IV → P.
The colour of the solution observed after about 1 hour of placing iron nails in copper sulphate solution is:
Let $ P(x_1, y_1) $ and $ Q(x_2, y_2) $ be two distinct points on the ellipse $$ \frac{x^2}{9} + \frac{y^2}{4} = 1 $$ such that $ y_1 > 0 $, and $ y_2 > 0 $. Let $ C $ denote the circle $ x^2 + y^2 = 9 $, and $ M $ be the point $ (3, 0) $. Suppose the line $ x = x_1 $ intersects $ C $ at $ R $, and the line $ x = x_2 $ intersects $ C $ at $ S $, such that the $ y $-coordinates of $ R $ and $ S $ are positive. Let $ \angle ROM = \frac{\pi}{6} $ and $ \angle SOM = \frac{\pi}{3} $, where $ O $ denotes the origin $ (0, 0) $. Let $ |XY| $ denote the length of the line segment $ XY $. Then which of the following statements is (are) TRUE?