Question

LIST-I contains compounds and LIST-II contains reaction
 

LIST-I		LIST-II
I	$\text{H}_2\text{O}_2$	P	$\text{Mg(HCO}_3\text{)}_2 + \text{Ca(OH)}_2 \rightarrow$
II	$\mathrm{Mg(OH)_2}$	Q	$\text{BaO}_2 + \text{H}_2\text{SO}_4 \rightarrow$
III	$\text{BaCl}_2$	R	$\text{Ca(OH)}_2 + \text{MgCl}_2$
IV	$\text{CaCO}_3$	S	$\text{BaO}_2 + 2\text{HCl} \rightarrow$
		T	$\text{Ca(HCO}_3\text{)}_2 + 2\text{Ca(OH)}_2 \rightarrow$

Match each compound in LIST – I with its formation reaction(s) in LIST-II, and choose the correct option

• A. I → Q; II → P; III → S; IV → R
• B. I → T; II → P; III → Q; IV → R
• C. I → T; II → R; III → Q; IV → P
• D. I → Q; II → R; III → S; IV → P

Answer 1

The Correct Option is D

(P) $\text{Mg(HCO}_3\text{)}_2 + 2\text{Ca(OH)}_2 \rightarrow \text{Mg(OH)}_2 + 2\text{CaCO}_3 + 2\text{H}_2\text{O}$ 
(Q) $\text{BaO}_2 + \text{H}_2\text{SO}_4 \rightarrow \text{H}_2\text{O}_2 + \text{BaSO}_4$
(R) $\text{Ca(OH)}_2 + \text{MgCl}_2 \rightarrow \text{Mg(OH)}_2 + \text{CaCl}_2$
(S) $\text{BaO}_2 + 2\text{HCl} \rightarrow \text{BaCl}_2 + \text{H}_2\text{O}_2$
(T) $\text{Ca(HCO}_3\text{)}_2 + \text{Ca(OH)}_2 \rightarrow 2\text{CaCO}_3 + 2\text{H}_2\text{O}$
I → Q

II → R

III → S

IV → P

Option (D) is correct.