Question:

LIST-I contains compounds and LIST-II contains reaction
 

LIST-I

LIST-II

I\(\text{H}_2\text{O}_2\)P\(\text{Mg(HCO}_3\text{)}_2 + \text{Ca(OH)}_2 \rightarrow \)
II\(\mathrm{Mg(OH)_2}\)Q\(\text{BaO}_2 + \text{H}_2\text{SO}_4 \rightarrow \)
III\(\text{BaCl}_2\)R\(\text{Ca(OH)}_2 + \text{MgCl}_2 \)
IV\(\text{CaCO}_3\)S\(\text{BaO}_2 + 2\text{HCl} \rightarrow\)
  T\(\text{Ca(HCO}_3\text{)}_2 + 2\text{Ca(OH)}_2 \rightarrow \)

Match each compound in LIST – I with its formation reaction(s) in LIST-II, and choose the correct option

Updated On: May 25, 2024
  • I → Q; II → P; III → S; IV → R

  • I → T; II → P; III → Q; IV → R

  • I → T; II → R; III → Q; IV → P

  • I → Q; II → R; III → S; IV → P

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The Correct Option is D

Solution and Explanation

(P) \(\text{Mg(HCO}_3\text{)}_2 + 2\text{Ca(OH)}_2 \rightarrow \text{Mg(OH)}_2 + 2\text{CaCO}_3 + 2\text{H}_2\text{O}\) 
(Q) \(\text{BaO}_2 + \text{H}_2\text{SO}_4 \rightarrow \text{H}_2\text{O}_2 + \text{BaSO}_4\)
(R) \(\text{Ca(OH)}_2 + \text{MgCl}_2 \rightarrow \text{Mg(OH)}_2 + \text{CaCl}_2\)
(S) \(\text{BaO}_2 + 2\text{HCl} \rightarrow \text{BaCl}_2 + \text{H}_2\text{O}_2\)
(T) \(\text{Ca(HCO}_3\text{)}_2 + \text{Ca(OH)}_2 \rightarrow 2\text{CaCO}_3 + 2\text{H}_2\text{O}\)
I → Q

II → R

III → S

IV → P

Option (D) is correct.

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