Question:
Light with an average flux of $20\,\Omega/cm^2$ falls on a non-reflecting surface at normal incidence having surface area $20\,cm^2$. The energy received by the surface during time span of $1\,minute$ is :
Light with an average flux of $20\,\Omega/cm^2$ falls on a non-reflecting surface at normal incidence having surface area $20\,cm^2$. The energy received by the surface during time span of $1\,minute$ is :
Updated On: Apr 14, 2025
- $10 \times 10^3J$
- $12 \times 10^3J$
- $24 \times 10^3J$
- $48 \times 10^3J$
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The Correct Option is C
Solution and Explanation
Energy received = Intensity $\times$ Area $\times$ Time
$I=\frac{E}{A}$
$E=IAt$
$=\frac{20}{10^{-4}}\times 20\times 10^{-4}\times 60$
$=24 \times 10^{3}\,J$
$I=\frac{E}{A}$
$E=IAt$
$=\frac{20}{10^{-4}}\times 20\times 10^{-4}\times 60$
$=24 \times 10^{3}\,J$
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