- Option (A) is true because a time-homogeneous Markov chain always has at least one recurrent state.
- Option (B) is false because if there is an absorbing state, it does not necessarily guarantee the existence of a stationary distribution.
- Option (C) is true because if all states are positive recurrent, a unique stationary distribution exists.
- Option (D) is true by the fundamental limit theorem of Markov chains, which states that for an irreducible Markov chain with a stationary distribution, \( \lim_{n \to \infty} P(X_n = i \mid X_0 = i) = \pi_i \).
Final Answer:
\[
\boxed{\text{(D) If \( \{X_n\}_{n \geq 0} \) is irreducible, \( S = \{1, 2\} \) and \( [\pi_1 \, \pi_2] \) is a stationary distribution, then \( \lim_{n \to \infty} P(X_n = i \mid X_0 = i) = \pi_i \).}}
\]