Step 1: Compactness of \( X \).
The space \( {R}/{Z} \) is compact because \( {R} \) is locally compact, and the quotient by \( {Z} \) identifies points separated by integers, creating a compact topology.
Step 2: Connectedness of \( X \setminus \{z\} \).
Removing a point from \( {R}/{Z} \) does not disconnect the space, as \( {R}/{Z} \) is homeomorphic to a circle, and a circle remains connected after the removal of a single point.
Step 3: Conclusion.
Both statements are true. The correct answer is \( {(1)} \).