Question:
Let X be a random variable having binomial distribution with parameters n(> 1) and p(0 < p < 1). Then \(E(\frac{1}{1+X})\) equals
Let X be a random variable having binomial distribution with parameters n(> 1) and p(0 < p < 1). Then \(E(\frac{1}{1+X})\) equals
Updated On: Oct 1, 2024
- \(\frac{1-(1-p)^{n+1}}{(n+1)p}\)
- \(\frac{1-p^{n+1}}{(n+1)(1-p)}\)
- \(\frac{(1-p)^{n+1}}{n(1-p)}\)
- \(\frac{1-p^{n}}{(n+1)p}\)
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The Correct Option is A
Solution and Explanation
The correct option is (A) : \(\frac{1-(1-p)^{n+1}}{(n+1)p}\).
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