Question

Let \( x<0.50 \), \( 0<y<1 \), \( z>1 \). What is the median of x, y, z?

• A. less than 1
• B. between 0 and 1
• C. greater than 1
• D. cannot say

Hint:

Median of three distinct ordered numbers is always the one in the middle.

Answer 1

The Correct Option is B

Given: - \( x<0.50 x<y \) - \( y \in (0, 1) y<z \) So we have: \[ x<y<z \text{Median = middle value = } \boxed{y} \] And \( y \in (0, 1) \), so: \[ \boxed{\text{between 0 and 1}} \]