To determine which of the statements regarding the function \( u \) are true, we will examine both statements using the given differential equation:
The function \( u: \mathbb{R} \to \mathbb{R} \) is specified to be twice continuously differentiable, with \( u(0) > 0 \) and \( u'(0) > 0 \). It satisfies the differential equation:
\(u''(x) = \frac{u(x)}{1 + x^2}\) for all \( x \in \mathbb{R} \).
We need to evaluate the derivative of the function \( uu' \):
\(\frac{d}{dx}(uu') = u'u' + uu'' = (u')^2 + u\frac{u}{1+x^2}\).
This can be expressed as:
\(\frac{d}{dx}(uu') = (u')^2 + \frac{u^2}{1+x^2}\).
Since \( (u')^2 \geq 0 \) and \(\frac{u^2}{1+x^2} \geq 0\) for all \( x \), we have:
\(\frac{d}{dx}(uu') \geq 0\).
Thus, \( uu' \) is monotonically increasing on \([0, \infty)\).
To investigate, consider the sign of \( u'(x) \). Initially, \( u'(0) > 0 \) is given.
Additionally, from the differential equation \( u''(x) = \frac{u(x)}{1+x^2} \), and since \( u(x) > 0 \), it implies \( u''(x) \geq 0 \).
This indicates that \( u'(x) \) is non-decreasing, i.e., \( u'(x) \geq u'(0) > 0 \) for \( x \in [0, \infty)\).
Therefore, \( u \) is monotonically increasing on \([0, \infty)\).
Both statements I and II are verified to be true with the given conditions.
Therefore, the correct answer is:
Both I and II are true.
Let \( f : [1, \infty) \to [2, \infty) \) be a differentiable function. If
\( 10 \int_{1}^{x} f(t) \, dt = 5x f(x) - x^5 - 9 \) for all \( x \ge 1 \), then the value of \( f(3) \) is ______.