Question:

Let the function \( f(x) \) be defined as: \[ f(x) = \begin{cases} A + x, & {if } x<2
1 + x^2, & {if } x \geq 2 \end{cases} \] If the function \( f(x) \) is continuous at \( x = 2 \), the value of \( A \) is \_\_\_\_\_.

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For continuity at a point, the left-hand limit and the right-hand limit must be equal at that point.
Updated On: Apr 10, 2025
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The Correct Option is C

Solution and Explanation

For continuity at \( x = 2 \), the left-hand limit (as \( x \to 2^- \)) must equal the right-hand limit (as \( x \to 2^+ \)). 1. Left-hand limit at \( x = 2 \):
For \( x<2 \), \( f(x) = A + x \). Thus, \[ \lim_{x \to 2^-} f(x) = A + 2 \] 2. Right-hand limit at \( x = 2 \):
For \( x \geq 2 \), \( f(x) = 1 + x^2 \). Thus, \[ \lim_{x \to 2^+} f(x) = 1 + 2^2 = 1 + 4 = 5 \] For continuity, these two limits must be equal: \[ A + 2 = 5 \quad \Rightarrow \quad A = 3 \]
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