Question:
Let the function $f:[0,1] \rightarrow R$ be defined by
$f(x)=\frac{4^{x}}{4^{x}+2}$.
Then the value of
$f\left(\frac{1}{40}\right)+f\left(\frac{2}{40}\right)+f\left(\frac{3}{40}\right)+\ldots+f\left(\frac{39}{40}\right)-f\left(\frac{1}{2}\right)$
is ____
Let the function $f:[0,1] \rightarrow R$ be defined by
$f(x)=\frac{4^{x}}{4^{x}+2}$.
Then the value of
$f\left(\frac{1}{40}\right)+f\left(\frac{2}{40}\right)+f\left(\frac{3}{40}\right)+\ldots+f\left(\frac{39}{40}\right)-f\left(\frac{1}{2}\right)$
is ____
$f(x)=\frac{4^{x}}{4^{x}+2}$.
Then the value of
$f\left(\frac{1}{40}\right)+f\left(\frac{2}{40}\right)+f\left(\frac{3}{40}\right)+\ldots+f\left(\frac{39}{40}\right)-f\left(\frac{1}{2}\right)$
is ____
Updated On: May 13, 2024
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Correct Answer: 19
Solution and Explanation
Answer is 19.
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